Answer: 0.0 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of butane
b) moles of oxygen
According to stoichiometry :
2 moles of butane require 13 moles of 
Thus 0.09 moles of butane will require =
of
Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.
Thus all the butane will be consumed and 0.0 grams of butane will be left.
<span>7.39 ml
For this problem, simply divide the mass of mercury you have by it's density.
100 g / 13.54 g/ml = 7.3855 ml
Since we only have 3 significant digits in 100., you need to round the result to 3 significant digits. So
7.3855 ml = 7.39 ml</span>
Answer:
Reverse the 
reaction
Explanation:
Reactions:
Overall:
As can be seen, in the overall reaction we have 
in the reactants like in the second reaction and 
in the products. The is in the first reaction but as a reactant so we need to reverse that reaction:
Combining:
Answer:
% of n-propyl chloride = 43.48 %
Explanation:
There are 2 secondary hydrogens and 6 primary hydrogens
The rate of abstraction of seondary hydrogen = 3.9 X rate of abstraction of primary hydrogen
probability of formation of isopropyl chloride = 3.9 X 1 (relative rate X relative number of secondary hydrogens)
Probability of formation of n-propyl chloride = 1 X 3 (relative rate X relative number of primary hydrogens)
Total probability = 3.9
% of n-propyl chloride = 3 X 100 / 6.9 = 43.48 %
