The solution of the system can be x - 3y = 4 only if both the equations can be simplified to x - 3y = 4.
This will mean that both the equations will result in the same line which is x - 3y = 4 and thus have infinitely many solutions.
Second equation is:
Qx - 6y = 8
Taking 2 common we get:
(Q/2)x - 3y = 4
Comparing this equation to x- 3y = 4, we can say that
Q/2 = 1
So,
Q = 2
Therefore, the second equation will be:
2x - 6y = 8
Answer:
yes
Step-by-step explanation:
I think sorry if I am wrong
Isolate the x in both cases. What you do to one side, you do to the other.
11x + 4 < 15
Subtract 4 from both sides
11x + 4 (-4) < 15 (-4)
11x < 11
isolate the x, divide 11 from both sides
11x/11 < 11/11
x< 1
x < 1 is your answer for the first one
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Again, isolate the x.
12x - 7 > -25
Add 7 to both sides
12x - 7 (+7) > -25 (+7)
12x > -18
Isolate the x, divide 12 from both sides
12x/12 > -18/12
x > -1.5 is your answer for the second one.
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hope this helps
The answer is D. The family would want to sale more or equal to what the cost is. 10,100 is 54 dollars too short how ever 10,200 is 46$ over what they need which is what they need.
Answer:
C , 18
Step-by-step explanation: