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3 years ago

What is the range of this relation? {(0,5), (2,3), (1, -4), (-3, 3), (-1, -2)}

Mathematics

2 answers:

Vadim26 [7]3 years ago

8 0

Answer:

The Answer is 5,3,-4,3,-2 because they are the points on the y axis

vredina [299]3 years ago

8 0

Step-by-step explanation:

the range = { -4, -2, 3, 5}

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Nikki and her four friends had lunch at their favorite restaurant. The total bill was $29.00, and they wanted to leave a 15% tip

Butoxors [25]

Answer:

$4.35

Step-by-step explanation:

Knowns:

Total bill: $29.00

Tip of 15% ($29.00)

Work:

$29.00 (0.15) = $4.35 tip

Hope this helps!

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3 years ago

Solve by quadratic equation

Ymorist [56]

<h2>Question :</h2>

$\tt \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}$

<h2>Answer :</h2>

$\large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}$

<h2>Explanation :</h2>

$\tt : \implies \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}$

$\tt : \implies \dfrac{(x+2)(x+2) + (x-2)(x-2)}{(x-2)(x+2)} = \dfrac{5}{6}$

$\tt : \implies \dfrac{(x+2)^{2} + (x-2)^{2}}{(x-2)(x+2)} = \dfrac{5}{6}$

<u>Now, we know that</u> :

$\large \underline{\boxed{\bf{(a+b)^{2} = a^{2} + b^{2}+ 2ab}}}$
$\large \underline{\boxed{\bf{(a-b)^{2} = a^{2} + b^{2} - 2ab}}}$
$\large \underline{\boxed{\bf{(a+b)(a-b) = a^{2} - b^{2}}}}$

$\tt : \implies \dfrac{x^{2}+2^{2}+ 2 \times x \times 2 + x^{2}+2^{2} - 2 \times x \times 2 }{x^{2}-2^{2}} = \dfrac{5}{6}$

$\tt : \implies \dfrac{x^{2}+ 4 + \cancel{4x} + x^{2}+ 4 - \cancel{4x}}{x^{2}-4} = \dfrac{5}{6}$

$\tt : \implies \dfrac{x^{2} + x^{2} + 4 + 4}{x^{2}-4} = \dfrac{5}{6}$

$\tt : \implies \dfrac{2x^{2} + 8}{x^{2}-4} = \dfrac{5}{6}$

<u>By cross multiply</u> :

$\tt : \implies (2x^{2} + 8)6= 5(x^{2}-4)$

$\tt : \implies 12x^{2} + 48 = 5x^{2}-20$

$\tt : \implies 12x^{2} + 48 - 5x^{2} + 20 = 0$

$\tt : \implies 7x^{2} + 68 = 0$

$\tt : \implies 7x^{2} + 0x + 68 = 0$

<u>Now, by comparing with ax² + bx + c = 0, we have</u> :

a = 7
b = 0
c = 68

<u>By using quadratic formula</u> :

$\large \underline{\boxed{\bf{x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}}}$

$\tt : \implies x = \dfrac{-(0) \pm \sqrt{(0)^{2} - 4(7)(68)}}{2(7)}$

$\tt : \implies x = \dfrac{0 \pm \sqrt{0 - 1904}}{14}$

$\tt : \implies x = \dfrac{\pm \sqrt{- 1904}}{14}$

$\tt : \implies x = \dfrac{\pm \sqrt{2\times 2\times 2\times 2\times 7\times 17}}{14}$

$\tt : \implies x = \dfrac{\pm \cancel{2} \times 2\sqrt{7\times 17}}{\cancel{14}}$

$\tt : \implies x = \dfrac{\pm2\sqrt{119}}{7}$

$\large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}$

Hence value of $\bf x =\dfrac{\pm 2\sqrt{119}}{7}$

5 0

3 years ago

Read 2 more answers

Determine the equation of the line that is parallel to y=23x+4 and passes through the point (3,7).

Licemer1 [7]

Answer: y = 23x - 62

<u>Step-by-step explanation:</u>

Parallel lines have the same slope.

y = 23x + 4

m=23 b=4

Input x = 3, y = 7, & m = 23 into the Point-Slope formula to find the equation or the Slope-Intercept formula to find b (you already have m). I will choose the latter.

y = mx + b

7 = 23(3) + b

7 = 69 + b

-62 = b

m = 23, b = -62 --> y = 23x - 62

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3 years ago

If a radius of a circle is 12 feet, what is the area and perimeter of the circle?

Vesna [10]

Area of a circle=πr²
area of this cirlce=π*(12 ft)²=144π ft²≈452.39 ft².

answer 1= the area of this circle is 452.39 ft².

Perimeter of a circle=2πr.
Perimeter of this cirlce=2π(12 ft)=24π ft≈75.4 ft

<span>answer 2= the perimeter of this cirlce is 75.4 ft.</span>

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3 years ago

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iVinArrow [24]

Answer:

The answer is C

Step-by-step explanation:

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