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Ganezh [65]
2 years ago
8

34. Lora is thinking of a number. It is less than 50 It is a 2-digit number. 3 is a factor of this number. The sum of its digits

is one third of the number What number is Lora thinking of? 8 A. 33 B. 27 C. 12 D. 36​
Mathematics
1 answer:
-Dominant- [34]2 years ago
8 0

Answer:

B

Step-by-step explanation:

The number is between 10 and 49

The number is divisible by 3

Let the 10s digit = x

Let the units digit = y

1/3 * (10x + y)  = x + y          multiply both sides by 3

10x + y = 3(x +y)                  remove the brackets.

10x +y = 3x + 3y                  Subtract 3x from both sides

10x - 3x + y = 3y                  Combine\

7x + y = 3y                           Subtract y from both sides.

7x = 3y - y                           Combine

7x = 2y

x can't be very big. Even taking 1/3 will get out of range is you use 6.

Also x should be an even number. The units digit cannot have a fraction in it.

Try making x = 2

7*2 = 2*y

14 = 2y                                Divide by 2

14/2 = y

y = 7

So the number is possibly 27. Let's check it out.

  • The number is between and includes 10 and 49. 27 is between these two endpoints.
  • 27 is divisible by 3
  • 1/3(27) = sum of digits
  • 9 = (2 + 7)

All of the conditions are met. It's B

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2 years ago
Suppose that your boss must choose three employees in your office to attend a conference in Jamaica. Because all 17 of you want
Pani-rosa [81]

Answer:

P(You\ n\ Anna\ n\ Kevin) = \frac{1}{4913}

Step-by-step explanation:

Given

Total\ Employees = 17

To\ Select = 3

Required

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Assuming the selection process is fair;

Each employee has a probability of;

Probability = \frac{1}{17}

So:

P(You\ n\ Anna\ n\ Kevin) = P(You) * P(Anna) * P(Kevin)

P(You\ n\ Anna\ n\ Kevin) = \frac{1}{17} * \frac{1}{17} * \frac{1}{17}

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5 0
3 years ago
Hello , I need help with these 2 problems. Could someone help me ?
saw5 [17]

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3 0
2 years ago
The cable between two towers of a suspension bridge can be modeled by the function shown, where x and y are measured in feet. Th
hodyreva [135]

a) x = 200 ft

b) y = 50 ft

c)

Domain: 0\leq x \leq 400

Range: 50\leq y \leq 150

Step-by-step explanation:

a)

The function that models the carble between the two towers is:

y=\frac{1}{400}x^2-x+150

where x and y are measured in feet.

Here we want to find the lowest point of the cable: this is equivalent to find the minimum of the function y(x).

In order to find the minimum of the function, we have to calculate its first derivative and require it to be zero, so:

y'(x)=0

The derivative of y(x) is:

y'(x)=\frac{1}{400}\cdot 2 x^{2-1}-1=\frac{1}{200}x-1

And requiring it to be zero,

\frac{1}{200}x-1=0

Solving for x,

\frac{1}{200}x=1\\x=200 ft

b)

In order to find how high is the road above the water, we have to find the value of y (the height of the cable) at its minimum value, because that is the point where the cable has the same height above the water as the road.

From part a), we found that the lowest position of the cable is at

x=200 ft

If we now substitute this value into the expression that gives the height of the cable,

y=\frac{1}{400}x^2-x+150

We can find the lowest height of the cable above the water:

y=\frac{1}{400}(200)^2-200+150=50 ft

Therefore, the height of the road above the water is 50 feet.

c)

Domain:

The domain of a function is the set of all possible values that the independent variable x can take.

In this problem, the extreme points of the domain of this function are represented by the position of the two towers.

From part a), we calculated that the lowest point of the cable is at x = 200 ft, and this point is equidistant from both towers. If we set the position of the tower on the left at

x=0 ft

then this means that the tower on the right is located at

x=400 ft

So the domain is 0\leq x \leq 400

Range:

The range of a function is the set of all possible values that the dependent variable y can take.

In this problem, the extreme points of the range of this function are represented by the highest points of the two towers.

In this problem, the first tower is located at

x = 0

So its height is

y=\frac{1}{400}\cdot 0^2 - 0+150 = 150 ft

Similarly, we can check that the height of the right tower located at

x = 400 ft

is the same:

y=\frac{1}{400}\cdot 400^2 -400+150=150 ft

The minimum value of y instead is the one calculated in part b), so

y = 50 ft

So the range of the function is

50\leq y \leq 150

6 0
3 years ago
What is the product of (-4x2-5x-1)(4x2-6x-2)
Stells [14]
(-4x2-5x-1)(4x2-6x-2)

Final result :

-2 • (13x + 1) • (2x2 - 3x - 1)
Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(-13x - 1) • ((22x2 - 6x) - 2)
Step 2 :

Pulling out like terms :

3.1 Pull out like factors :

-13x - 1 = -1 • (13x + 1)

Step 3 :

Pulling out like terms :

4.1 Pull out like factors :

(4x2 - 6x - 2) = 2 • (2x2 - 3x - 1)

Trying to factor by splitting the middle term

4.2 Factoring 2x2 - 3x - 1

The first term is, 2x2 its coefficient is 2 .
The middle term is, -3x its coefficient is -3 .
The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 2 • -1 = -2

Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is -3 .

-2 + 1 = -1
-1 + 2 = 1

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Step 4 :

Pulling out like terms :

5.1 Pull out like factors :

-26x - 2 = -2 • (13x + 1)

Final result :

-2 • (13x + 1) • (2x2 - 3x - 1)
7 0
3 years ago
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