All categories

3 years ago

whether the distribution of the mean of a large number of independent, identically distributed variables. true or false

Mathematics

1 answer:

san4es73 [151]3 years ago

6 0

Answer:

The statement is false

Step-by-step explanation:

Given

See comment for complete statement

Required

Is the statement true or false

From central limit theorem, we understand that a distribution is approximately normal if the distribution takes a sample considered to be large enough from the population.

Also, the mean and the standard deviation are known.

However, the given statement implies that the distribution will be normal depending on an underlying distribution; this is false.

You might be interested in

F(x)=4x squared −7x+7, Find f(2)

Lana71 [14]

Answer: 9

Step-by-step explanation:

4x²-7x+7 f(2)=4*(2)^2-7(2)+7=16-14+7=9

7 0

3 years ago

PLEASE HELP IMMEDIATELY!!!! Find x when – Negative one-half + x = –Negative StartFraction 21 over 4 EndFraction. – Negative Star

balu736 [363]

Answer:

-61/4

Step-by-step explanation:

-1/2 + x = - 21/4 - 23/4 - 19/4

-1/2 + x = -(21+23+19)/4

x = -63/4 + 1/2

x= -63/4 + 2/4

x = -61/4

Hope that helps, tell me if you need further explanation. =)

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D%20p%20%2B%206%20%3D%20-%5Cfrac%7B1%7D%7B3%7Dp%20-3" id="TexFormula1" tit

Likurg_2 [28]

P= - 135/7 I am pretty sure that’s the answer

8 0

3 years ago

Use matrices and elementary row to solve the following system:

LiRa [457]

I assume the first equation is supposed to be

$5x-3y+2z=13$

and not

$5x-3x+2x=4x=13$

As an augmented matrix, this system is given by

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]$

Multiply through row 3 by 1/2:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]$

Multiply through row 3 by 1/5:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]$

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

$\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -3(row 2) to row 1:

$\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Multiply through row 1 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -2(row 1) to row 2:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]$

Multipy through row 2 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]$

The solution to the system is then

$\boxed{x=1,y=-2,z=1}$

5 0

3 years ago

Markuo spends $27 on some plants. Each plant costs $9. How many plants does he buy?

kicyunya [14]

Answer:

He can buy 3 plants

Step-by-step explanation:

$27 is the total amount of money he can spend, if each plant costs $9 the equation would be like this:

9x = 27

Divide 27 by 9 because division is the opposite operation to multiplication

x = 3

6 0

3 years ago