Answer:
The statement is false.
Step-by-step explanation:
If the modeling is with multiple variables it is necessary for all the variables to be modeled well such that the criticality of the model is dependent on all the variograms. It is not dependent on the cross variograms only.
Answer:
-2×h
Step-by-step explanation:
because it drops-2 by hour so multiply-2 by the difference of hours
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
Answer:
Either <em><u>10 times</u></em> or <u><em>598,000.</em></u>
Step-by-step explanation:
6 x 10 ^ 5 = 600,000
2 x 10 ^ 3 = 2,000
If we are figuring out the exact number, 600,000 - 2,000. If we are finding out how many powers larger, count.
600,000 - 2,000 = 598,000
600,000 is 10 times larger than 2,000.
See?
600,0<u>00</u>
2,000
A solution to a division problem means it is the quotient. And it tells us the solution to the dividend and divisor.
