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adell [148]
3 years ago
15

Which of the following will increase if the voltage in a circuit is increased?

Physics
2 answers:
Gemiola [76]3 years ago
5 0
If the voltage used to operate a circuit is increased, then
the current flowing at every point in the circuit will increase,
and the power radiated by the components in the circuit will
also increase. 

If you increase the voltage TOO much, then you may need to
start cooling the circuit to prevent fire, or to prevent components
from failing.
babymother [125]3 years ago
4 0

The answer is A and D.

The relationship between power current and voltage is given by the following equation;

P=IV

P = power

V = voltage

I = current

When the voltage (V is increased and the current (I) is maintained, then the power will definitely increase.

Increasing the voltage also increases the distance that the power can be transmitted with little attenuation or loss. This is why voltage is usually stepped up (which will reduce current) significantly at power stations before it's transmission over long distances.


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A prismatic bar AB of length L and solid circular cross section (diameter d) is loaded by a distributed torque of constant inten
Lyrx [107]

Answer:

a) the maximum shear stress τ_{max} the bar is 16T_{max} /πd³

b) the angle of twist between the ends of the bar is 16tL² / πGd⁴  

Explanation:

Given the data in the question, as illustrated in the image below;

d is the diameter of the prismatic bar of length AB

t is the intensity of distributed torque

(a) Determine the maximum shear stress tmax in the bar

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we know that;

shear stress τ = 16T/πd³

where d is the diameter

so

τ_{max} = 16T_{max} /πd³

Therefore, the maximum shear stress τ_{max} the bar is 16T_{max} /πd³

(b) Determine the angle of twist between the ends of the bar.

let theta (\theta) be the angle of twist

polar moment of inertia I_p} = πd⁴/32

now from the second image;

lets length dx which is at distance of "x" from "B"

Torque distance x

T(x) = tx

Elemental angle twist = d\theta = T(x)dx / GI_{p}

so

d\theta = tx.dx / G(πd⁴/32)

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\theta =  \int\limits^L_0  \, d\theta

\theta =  \int\limits^L_0  \, 32tx.dx / πGd⁴

\theta = 32t / πGd⁴  \int\limits^L_0  \, xdx

\theta = 32t / πGd⁴ [ L²/2]

\theta = 16tL² / πGd⁴  

Therefore,  the angle of twist between the ends of the bar is 16tL² / πGd⁴  

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3 years ago
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Answer:

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Δx = (20.5 m/s) (20 s) + ½ (0 m/s²) (20 s)²

Δx = 410 m

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