1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
strojnjashka [21]
3 years ago
7

When planning an oral presentation, you want to make sure to do all of the following except _____.

Physics
2 answers:
Lelu [443]3 years ago
6 0

All of the items on your list are good to include in the plan.

Sindrei [870]3 years ago
3 0

are there answer choices?

You might be interested in
A 75kg man climbs the stairs to the fifth floor of a building. A total hieght of 16m. His potential energy has increased by
yKpoI14uk [10]

Answer:

11760 joules

Explanation:

Given

Mass (m) = 75kg

Height (h) = 16m

Required

Determine the increment in potential energy (PE)

This is calculated as thus:

PE = mgh

Where g = 9.8m/s²

Substitute values for m, g and h.

P.E = 75 * 9.8 * 16

P.E = 11760 joules

8 0
3 years ago
Help please this is important!
bixtya [17]

Answer:

Since the ball becomes positively charged, it will repel as like charges repel.

7 0
3 years ago
What are four characteristics of environments near the shore?
Dimas [21]

Answer I don’t knows

Explanation: i don’t know I just want points

3 0
3 years ago
Read 2 more answers
Which elements do not usually interact with other elements?
d1i1m1o1n [39]
Noble gasses ( insert gases)
7 0
3 years ago
Read 2 more answers
Two light bulbs have resistances of 400 Ω and 800 ΩThe two light bulbs are connected in series across a 120- V line. Find the cu
Natasha2012 [34]

1) Current in each bulb: 0.1 A

The two light bulbs are connected in series, this means that their equivalent resistance is just the sum of the two resistances:

R_{eq}=R_1 + R_2 = 400 \Omega + 800 \Omega=1200 \Omega

And so, the current through the circuit is (using Ohm's law):

I=\frac{V}{R_{eq}}=\frac{120 V}{1200 \Omega}=0.1 A

And since the two bulbs are connected in series, the current through each bulb is the same.

2) 4 W and 8 W

The power dissipated by each bulb is given by the formula:

P=I^2 R

where I is the current and R is the resistance.

For the first bulb:

P_1 = (0.1 A)^2 (400 \Omega)=4 W

For the second bulb:

P_1 = (0.1 A)^2 (800 \Omega)=8 W

3) 12 W

The total power dissipated in both bulbs is simply the sum of the power dissipated by each bulb, so:

P_{tot} = P_1 + P_2 = 4 W + 8 W=12 W

3 0
3 years ago
Other questions:
  • What scientific breakthrough did Charles Darwin conclusion lead to? ANSSER ASAP PLZ
    12·1 answer
  • A material the resists the flow of electrons is called a
    15·1 answer
  • You're sitting on a warm granite rock, enjoying the sunshine. You decide it's time to test the water. You take off your shoes an
    10·1 answer
  • A 5.0 c charge is 10 m from a small test charge. what is the magnitude of the electric field at the location of the test charge
    11·1 answer
  • Your cat "Ms." (mass 7.00 {\rm kg}) is trying to make it to the top of a frictionless ramp 2.00 {\rm m} long and inclined upward
    6·1 answer
  • How do the parallel magnetic “stripes” near mid-ocean ridges form?
    10·2 answers
  • Drag each label to the correct location on the chart. Each label can be used more than once.
    9·1 answer
  • The car travels 25 miles in the first 0.5 hours
    15·1 answer
  • In Cathode Ray Oscilloscope (CRO), if plates for vertical deflection are removed then what will be the wave pattern on the fluor
    15·1 answer
  • A 3.1 kg ball is dropped from the top of a 38 m tall building. What is the speed of the ball when it is halfway from the buildin
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!