A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank
In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).
a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
Answer:
5x+31
Step-by-step explanation:
f(g(x))
5(x+7) -4
5x+35-4
5x+31=f(g(x))
Answer:
They are congruent by HL
Step-by-step explanation:
Please post the question with an attachment of what you want to be answered next time.
Answer:
10x^{3}[/tex]
Step-by-step explanation:
=10·10·10
=1000
