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Sladkaya [172]
3 years ago
8

Mechanical Energy

Chemistry
1 answer:
andreev551 [17]3 years ago
8 0

Answer:

A

Explanation:

A ball buried under the ground is the answer because it has no kinetic energy because of it's inability to move

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DUPLICATE
Svet_ta [14]
As in relative abundance , one is take reference
So,
One is taken as 1:
Other is subtracted from it:
(1 - 0.6011)(atomic mass of Ga-71) 

Equation can be written as:
<span>69.723 = (0.6011)(68.9256) + (1-0.6011)x </span>
<span>(1-0.6011) is the percentage abundance of Ga-71 expressed in percentage: </span>

<span>Solving for x </span>
<span>28.2918 = 0.3989 x </span>
<span>x= 70.9246.......</span>
7 0
3 years ago
GUYS QUICK HELP!<br> is a soda pop bottle a invention or an innovation?
Grace [21]

Answer:

Invention

Explanation:

!Hope This Helps!

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3 years ago
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Why do very few trees exist in a grassland ecosystem?
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<span>D. not enough precipitation is the answer</span>
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3 years ago
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Consider the reaction 2N2(g) O2(g)2N2O(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for t
ratelena [41]

Answer:

\Delta G^0 _{rxn} = 207.6\ kJ/mol

ΔG ≅ 199.91 kJ

Explanation:

Consider the reaction:

2N_{2(g)} + O_{2(g)} \to 2N_2O_{(g)}

temperature = 298.15K

pressure = 22.20 mmHg

From, The standard Thermodynamic Tables; the following data were obtained

\Delta G_f^0  \ \ \ N_2O_{(g)} = 103 .8  \ kJ/mol

\Delta G_f^0  \ \ \ N_2{(g)} =0 \ kJ/mol

\Delta G_f^0  \ \ \ O_2{(g)} =0 \ kJ/mol

\Delta G^0 _{rxn} = 2 \times \Delta G_f^0  \ N_2O_{(g)} - ( 2 \times  \Delta G_f^0  \ N_2{(g)} +   \Delta G_f^0  \ O_{2(g)})

\Delta G^0 _{rxn} = 2 \times 103.8 \ kJ/mol - ( 2 \times  0 +   0)

\Delta G^0 _{rxn} = 207.6\ kJ/mol

The equilibrium constant determined from the partial pressure denoted as K_p can be expressed as :

K_p = \dfrac{(22.20)^2}{(22.20)^2 \times (22.20)}

K_p = \dfrac{1}{ (22.20)}

K_p = 0.045

\Delta G = \Delta G^0 _{rxn} + RT \ lnK

where;

R = gas constant = 8.314 × 10⁻³ kJ

\Delta G =207.6 + 8.314 \times 10 ^{-3} \times 298.15  \ ln(0.045)

\Delta G =207.6 + 2.4788191 \times \ ln(0.045)

\Delta G =207.6+ (-7.687048037)

\Delta G = 199.912952  kJ

ΔG ≅ 199.91 kJ

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4 years ago
How much does the earth weigh?
Lady_Fox [76]

Answer:

5.972 × 10^24 kg  

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