<span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed:
a = omega^2*r
omega and r in terms of given data:
omega = 2*Pi/T
r = d/2
Thus:
a = 2*Pi^2*d/T^2
What forces cause this acceleration for the passenger, at either top or bottom?
At top (acceleration is downward):
Weight (m*g): downward
Normal force (Ntop): upward
Thus Newton's 2nd law reads:
m*g - Ntop = m*a
At top (acceleration is upward):
Weight (m*g): downward
Normal force (Nbottom): upward
Thus Newton's 2nd law reads:
Nbottom - m*g = m*a
Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame:
Ntop = m*(g - a)
Nbottom = m*(g + a)
Substitute a:
Ntop = m*(g - 2*Pi^2*d/T^2)
Nbottom = m*(g + 2*Pi^2*d/T^2)
We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground):
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g)
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g)
Simplify:
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2)
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2)
Data:
d:=22 m; T:=12.5 sec; g:=9.8 N/kg;
Results:
Ntop/(m*g) = 71.64%...she feels "light"
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
Answer:
$291.50
Step-by-step explanation:
For 22 hours, he earns 22 times his hourly pay.
22×$13.25 = $291.50
You can round 406to420 then divide by 7 or 406-490 divided by 7
Answer:
It is binomial:
p= 0.75 = 75%
1-p = 0.25 = 25%
N = 10
k=7
"seven successes in 10 trials"
(10 choose 7) (0.75)^7 ( 0.25)^3 =
(10*9*8 / 3*2) * (0.75)^7 ( 0.25)^3 =
(5*3*8) (0.75)^7 ( 0.25)^3
120 (0.75)^7 ( 0.25)^3
= 0.25028228759765625
or just over 25%
Step-by-step explanation:
Answer:
3*2+4=6+4=10 and 4*6+6-10=24+6-10=30-10=30
