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2 years ago

Help plz..And No links!! I repeat No links!!

Mathematics

1 answer:

BaLLatris [955]2 years ago

4 0

Answer:

Step-by-step explanation:

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Solve the inequality and enter your solution as an inequality comparing the

avanturin [10]

Answer: x > 20

Step-by-step explanation:

x + 10 > 30

-10 -10

x > 20

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3 years ago

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A used motorcycle is on sale for $3,600. Erik makes an offer equal to 3/4 of this price. How much does Erik offer for the motorc

lesantik [10]

3/4 of 3600..." of " means multiply
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3 years ago

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Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

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3 years ago

Let x and y represent two real numbers. Write an algebraic expression to denote the quotient obtained when the product of the tw

sertanlavr [38]

(xy)/(x+y) hope this helps

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3 years ago

Emma has addressed seven invitations to her

Firlakuza [10]

Answer:

Step-by-step explanation:

This can be solved by working backwards.

7 is one more than half the number of invitations.

Subtract 1. 6 is half the number of invitations.

Double.

12 is the full number of invitations.

Algebra (if you must!):

x = number of invitations

x/2 + 1 = 7

Subtract 1.

x/2 = 6

Multiply by 2.

x = 12

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2 years ago

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