Use heron's formula to find the area of the triangle. round to the nearest square unit

Mathematics

1 answer:

GarryVolchara [31]3 years ago

3 0

Did the question give you any lengths of the sides?

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ale4655 [162]

Answer:

$Area = 58 \ units^2$

Step-by-step explanation:

We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:

$a^2+b^2=c^2$

In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:

$3^2+7^2=c^2$

$9+49=c^2$

$c^2=58$

$c=\sqrt{58}$

Since the area of a square is the side length square then...

$Area =( \sqrt{58} )^2$

The square root and the squared cancel out giving us...

$Area = 58 \ units^2$

3 0

3 years ago

What’s the answer please help

noname [10]

Answer:

$\boxed{\text{A. }\math{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \}}}}$

Step-by-step explanation:

The open circle means that the point is not included in the solution set, and the arrow pointing left means that all numbers less than -2 are members.

In set-builder notation, each term has a special meaning. The braces enclose the members of the set.

Here's how you translate the notation,

$\begin{array}{rcl}\\\left \{ & = & \text{The set of}\\x & = & \text{all x values}\\| & = &\text{such that}\\x & = & x\\\in & = &\text{is a member of}\\\mathbb{R}, & = &\text{all real numbers, and}\\x < -2 & = & \text{x is less than -2}\\\end{array}\\\text{The answer is }\boxed{\textbf{A. }\mathbf{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \} }}}$