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dmitriy555 [2]
3 years ago
9

Find the area of the figure. Sides meet at right angles. No links please

Mathematics
1 answer:
OLga [1]3 years ago
3 0

Answer:

answer: 72

Hope that helps!

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Which sequences of transformations confirm the congruence of shape II and shape I?
mylen [45]

Answer:

1. When we reflect the shape I along X axis it will take the shape I in first quadrant, and then if we rotate the shape I by 90° clockwise, it will take the shape again in second quadrant . So we are not getting shape II. This Option is Incorrect.

2. Second Option is correct , because by reflecting the shape I across  X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.

3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.

4. This option is correct, because after reflecting the shape through Y axis ,and then rotating the shape through an angle of 90° in clockwise direction takes it in second quadrant.

5. A reflection of shape I across the x-axis followed by a 180° rotation about the origin takes the shape I in third quadrant.→→Incorrect option

6 0
3 years ago
Read 2 more answers
(6e−3f−4)⋅2=<br> otay otay
Dmitry [639]

Answer:

Step-by-step explanation:

if you need to evaluate the expression:

multiply 2 with the parenthesis

12e-6f-8

8 0
3 years ago
Read 2 more answers
Please help me this is urgent.!
nata0808 [166]
V= 3.14• 5^2•4
V= 3.14 •25•4
V= 78.5•4
V=314

Sorry I couldn’t give a more detailed explanation but here is the original equation for volume of a cylinder:

V=πr2h

Hope this helps comment below for more questions :)
3 0
3 years ago
Read 2 more answers
4. Line t and AECA and AFDB are shown on the coordinate plane
julia-pushkina [17]

Answer:

A, B, C, E

Step-by-step explanation:

It can be seen from the figure that the points A, B, C and D, all are lying in the line t.

=> So that it can be concluded that AC and BC and BD have the slopes which are equal to each other and also equal to the slop of line t

So that all answer A, B, C are true.

In addition, as FD is parallel with x - axis, so that slope of the line t is equal to <em>tan angel FDB </em>

As FDB is the right triangle with BFD = 90°

=> tan angel FDB = FB/ FD (tan of an acute angel in the right triangle = opposite side/ adjacent side)

=> Slope of the line t is equal to FB/ FD

=> Answer E is true

6 0
3 years ago
Read 2 more answers
5/4 to 3/8 as a percent change
Digiron [165]
Well, what's the diffrence from 5/4 to 3/8?

\bf \cfrac{5}{4}-\cfrac{3}{8}\qquad \stackrel{\textit{LCD is 8 clearly}}{\implies }\qquad \cfrac{10-3}{8}\implies \cfrac{7}{8}

so, if we take 5/4 to be the 100%, what is 7/8 off of it in percentage anyway?

\bf \begin{array}{ccll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;\frac{5}{4}&100\\\\&#10;\frac{7}{8}&x&#10;\end{array}\implies \cfrac{\quad \frac{5}{4}\quad }{\frac{7}{8}}=\cfrac{100}{x}\implies \cfrac{5}{4}\cdot \cfrac{8}{7}=\cfrac{100}{x}&#10;\\\\\\&#10;\cfrac{40}{28}=\cfrac{100}{x}\implies x=\cfrac{28\cdot 100}{40}
5 0
3 years ago
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