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3 years ago

3/4w=9 what does w equal?

Mathematics

2 answers:

Setler [38]3 years ago

6 0

9/(3/4)=(36/3)
36/3=12
W=12

Studentka2010 [4]3 years ago

5 0

3/4 w = 9

multiply by 4/3 on both sides

4/3 x 3/4 w = 9 x 4/3

w = 9 x 4/3

Simplify that

w = 3 x 4

w = 12

So your final answer is

$\boxed{\bf{w=12}}$

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What is a coupon on a bond similar to?

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A coupon is a paper with a discount.

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4 years ago

Simplify the expression: 2x( 4x + 5)<br> A 622 + 72<br> B 82 + 5<br> C 812 + 103<br> D O81 +10

nexus9112 [7]

Answer:

=8x2+10x

Step-by-step explanation:

2x(4x+5)

=(2x)(4x+5)

=(2x)(4x)+(2x)(5)

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3 years ago

How do i solve 2+49x4+x

qaws [65]

Answer:

Step by step solution :

STEP1:Equation at the end of step 1

((49 • (x4)) - (2•7x2)) + 1 = 0

STEP 2 :

Equation at the end of step2:

(72x4 - (2•7x2)) + 1 = 0

STEP3:Trying to factor by splitting the middle term

3.1 Factoring 49x4-14x2+1

The first term is, 49x4 its coefficient is 49 .

The middle term is, -14x2 its coefficient is -14 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 49 • 1 = 49

Step-2 : Find two factors of 49 whose sum equals the coefficient of the middle term, which is -14 .

-49 + -1 = -50 -7 + -7 = -14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -7

49x4 - 7x2 - 7x2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

7x2 • (7x2-1)

Add up the last 2 terms, pulling out common factors :

1 • (7x2-1)

Step-5 : Add up the four terms of step 4 :

(7x2-1) • (7x2-1)

Which is the desired factorization

Step-by-step explanation:

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3 years ago

X-23 / x^2 -x- 20 - 2/5-x

alexira [117]

By simplifying $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$ . This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$

Since two opposites add up to 0, remove them from the expression.

$- \frac{{23}}{{{x^2}}} - \frac{{102}}{5} - x$

Write all numerators above the least common denominator 5x2

$- \frac{{115 + 102{x^2} + 5{x^3}}}{{5{x^2}}}$

Use the commutative property to reorder the terms so that constants on the left

$\frac{{ - 5{x^3} - 115 - 102{x^2}}}{{5{x^2}}}$

Rearrange the terms

$\frac{{ - 5{x^3} - 102{x^2} - 115}}{{5{x^2}}}$

By reording the terms

$- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$

Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

To learn more about simplifyication visit:

brainly.com/question/1542396

#SPJ1

7 0

1 year ago

Philip made a total of 9 bracelets and necklaces from 120 inches of cord. He used 8 inches of cord for each bracelet and 20 inch

Viktor [21]

Answer:

So Philip made 5 bracelets and 4 necklaces.

Step-by-step explanation:

Let x = number of bracelets and y = number of necklaces.

Since we have a total of 9 bracelets and necklaces,

x + y = 9 (1)

Also, we have 8 inches of cord for each bracelet and 20 inches of cord for each necklace, then the total length for the bracelet is 8x and that for the necklace is 20y.

So, the total length for both is 8x + 20y. Since the total length of cord used is 120 inches,

8x + 20y = 120 (2)

Simplifying it we have

2x + 5y = 30 (3).

Writing equations (1) and (3) in matrix form, we have

$\left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}9\\30\end{array}\right]$

Using Cramer's rule to solve for x and y,

$x = det \left[\begin{array}{ccc}9&1\\30&5\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\$

x = (9 × 5 - 30 × 1) ÷ (1 × 5 - 1 × 2)

x = (45 - 30) ÷ (5 - 2)

x = 15 ÷ 3

x = 5

$y = det \left[\begin{array}{ccc}1&9\\2&30\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\$

y = (30 × 1 - 9 × 2) ÷ (1 × 5 - 1 × 2)

y = (30 - 18) ÷ (5 - 2)

y = 12 ÷ 3

y = 4

So Philip made 5 bracelets and 4 necklaces.

3 0

3 years ago