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3 years ago

7

Jessie has been training for a half-marathon. Jesse trains on a track where each lap is 1/4 of a mile. If Jesse ran 3 1/7 miles,

how many laps did she run?

2 answers:

romanna [79]3 years ago

7 0

Answer:

88/7miles or 12 4/7

Step-by-step explanation:

divide 3 1/7 by 1/4

NISA [10]3 years ago

4 0

Answer:

14.2

Step-by-step explanation:

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If Seller Sam paid $488 for transfer taxes at closing, and the rate was $1.00 for every $400 or fraction thereof of the sale pri

sdas [7]

Answer: The selling price was $195,200

Step-by-step explanation:

Given:

Tax paid = $488

Rate = $1 per $400 = 1/400

Using the formula;

Tax = rate × selling price

Selling price = tax /rate

Selling price = $488/(1/400) = $488×400 = $195200

7 0

3 years ago

HELP WILL GIVE BRAINIEST IF ANSWERED FAST!!! HELP NOWWWW

maksim [4K]

33

Since it is parallel, that means that the line will have the same slope. Just simplify and add the x values in the first equation to get 33x.

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3 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

3 years ago

Last year, Scout Troop # 85 sold 540 boxes of cookies. This year, they sold 783 boxes. What was the percent increase in the numb

lesantik [10]

Difference/original
783 - 540 = 243
243/540 = 0.45
0.45 * 100 = 45
45% = increased percentage

4 0

3 years ago

GIVEN THAT TITAN HAS A RADIUS OF 2575 KM WHICH IS COVERED BY 600 KM ATMOSPHERE. WHAT

Ber [7]

Answer:

87.4%

Step-by-step explanation:

The radius to the top of the atmosphere as a fraction of the moon's radius is ...

(2575 +600)/2575 ≈ 1.23301

The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456

Then the ratio of the atmosphere's volume to the moon's volume is ...

(1.87456 -1)/1 = 0.87456

Atmospheric haze is about 87.4% of the moon's volume.

_____

We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.

3 0

4 years ago