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2 years ago

1 Which equation represents a line that has a slope of 3 and passes through point (-2, 1)?

Mathematics

1 answer:

enot [183]2 years ago

4 0

Well if the first point is (-2, 1) and the slope is three than the other point would be (-1, 4)

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Hi answer for this please

miv72 [106K]

Answer:

x+79degree + 35degree = 180 degree ( being the sum of all angle of the triangle )

or, x + 114 degree = 180 degree

or, x = 180degree - 114degree

or, x = 66degree

hence, x = 66 degree.

3 0

2 years ago

Anybody...Help!!!!!!!!!!!

Sloan [31]

Simple...

when they ask for the rate of change they ask for slope -->>

Using $\frac{ y_{1} - y_{2} }{ x_{1} - x_{2} }$ to find the rate of change for (-3,0) and (-2,-5)

$\frac{0--5}{-3--2}$

$\frac{0+5}{-3+2}$

$\frac{5}{-1}$

m=-5

Thus, your answer.

4 0

2 years ago

Answer for 14+3y < 65

ivanzaharov [21]

Hey there!

14 + 3y < 65

SOME people replace “<”, “>”, “≥”, or “≤” as an equal sign (=) to make it easier to solve

14 + 3y < 65
14 + 3y = 65

SUBTRACT by 14 on both of your sides
3y + 14 - 14 = 65 - 14
CANCEL out: 14 - 14 because that gives you 0
KEEP: 65 - 14 because it helps you solve for “y”

**65 - 14 = 51**

NEW EQUATION: 3y = 51

DIVIDE by 3 both of your sides
3y/3 = 51/3
CANCEL out: 3/3 because that gives you 1
KEEP: 51/3 because it gives you the value of “y”

NEW EQUATION: y = 51/3

**51/3 = 17**

Answer: y = 17 ☑️

☑️ OVERALL ANSWER FOR YOU: y < 17 ☑️
NOTE: it’s an OPEN circle SHADED to the LEFT

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0

3 years ago

Read 2 more answers

OMG HELP PLS IM PANICKING OMG OMG I GOT A F IN MATH AND I ONLY HAVE 1 DAY TO CHANGE MY GRADE BECAUSE TOMORROW IS THE FINAL REPOR

kherson [118]

A. You need to compare 2/5, 1/2 and 3/4
2/5= .4
1/2= .5
3/4=.75
Therefore the bucket that is 2/5 full is less than 1/2 full

8 0

2 years ago

Read 2 more answers

On the 1st January 2014 Carol invested some money in a bank account.

Ghella [55]

Answer:

$\large \boxed{\text{\pounds 23 360.00}}$

Step-by-step explanation:

The formula for the accrued amount from compound interest is

$A = P \left(1 + \dfrac{r}{n}\right)^{nt}$

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:

r = 0.025

$\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}$

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

$\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}$

3. Summary

1 Jan 2014 P = £23 360.00

1 Jan 2015 A = 23 944.00

Withdrawal = <u> -1 000.00 </u>

P = 22 944.00

1 Jan 2016 A = £23 517.60

5 0

2 years ago