1. You can use the formula V1/ T1 = V2/T2
Solve for V2 give than V1= 10.0 L, T1= 25 C= 298 K, T2= 10 C= 283 K.
(10.0L/298K)= V2/283K------> V2= 9.50 L.
I cant see the answer there.. weird!
2. you can use the formula P1V1= P2V2
solve for V2 given than P1= atm, V1= 2.0 L, P2= 300 atm.
(1atm)x(2.0L)= (300atm)V2----->0.00667 atm.
so answer is A.
Answer:
hola soy jess, tu respuesta esta aqui
¿cuantos moles de CO2 se requiere para reaccionar 2 moles de Ba(OH)2
2 mol Ba(OH)₂ × \frac{1molCO_{2} }{1molBa (OH)_{2}}
1molBa(OH)
2
1molCO
2
= 2 moles CO₂
Explanation:
espero que pueda ayudarte
hermana/hermano
lo que
hahahaha
The answer is n2+3h2=2nh3