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finlep [7]
3 years ago
12

Crude oil is derived from which of the following materials?

Chemistry
1 answer:
QveST [7]3 years ago
3 0

I believe that crude oil is derived from plants because it is made up of a liquid that is found beneath the earth surface so I guess you could go with plants it is not an animal or rock or salt so.. could be brainliest not 100% sure so if you are not sure go with your gut

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Jamie had $37 in his bank account on Sunday.
Alexandra [31]

Answer:

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T or D??/ anyone?
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Answer:

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Explanation:

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Calcium hydroxide, Ca(OH)2, is an ionic compound with a solubility product constant, Ksp, of 6.5×10–6. Calculate the solubility
kari74 [83]

Answer: The solubility of this compound in pure water is 0.012 M

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}

The equation for the ionization of the  is given as:

Ca(OH)_2\rightarrow Ca^{2+}+2OH^-  

By stoichiometry of the reaction:

1 mole of  Ca(OH)_2 gives 1 mole of Ca^{2+} and 2 mole of OH^-

When the solubility of  Ca(OH)_2 is S moles/liter, then the solubility of Ca^{2+}  will be S moles\liter and solubility of OH^- will be 2S moles/liter.

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6.5\times 10^{-6}=[S][2S]^2

S=0.012M

Thus solubility of this compound in pure water is 0.012 M

5 0
3 years ago
A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl
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The [OH-] of an aqueous solution is 3.5 x 10-5. What is the [H+]?
Sergeeva-Olga [200]

Answer: The concentration of hydrogen ion in the given solution is 2.81 \times 10^{-10}.

Explanation:

pOH of a solution is the negative logarithm of concentration of hydroxide ions.

Hence, if [OH^{-}] is 3.5 \times 10^{-5} then its pOH value is calculated as follows.

pOH = -log [OH^{-}]\\= -log (3.5 \times 10^{-5})\\= 4.45

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pH = 14 - 4.45

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And, pH is the negative logarithm of concentration of hydrogen ions. Hence, [H^{+}] is calculated as follows.

pH = -log [H^{+}]\\9.55 = -log [H^{+}]\\H^{+} = 2.81 \times 10^{-10}

Thus, we can conclude that the concentration of hydrogen ion in the given solution is 2.81 \times 10^{-10}.

4 0
3 years ago
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