Cuantos moles de CO2 se requieren para reaccionar con 2 moles de Ba (OH)2
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Answer:
40.1 g
Explanation:
The <em>balanced equation</em> is:
- Ca(ClO₃)₂ → CaCl₂ + 3O₂
First we <u>convert 86.5 g of calcium chlorate into moles</u>, using its<em> molar mass</em>:
- 86.5 g Ca(ClO₃)₂ ÷ 206.98 g/mol = 0.418 mol Ca(ClO₃)₂
Then we <u>convert Ca(ClO₃)₂ moles into O₂ moles</u>, using <em>the stoichiometric coefficients of the balanced reaction</em>:
- 0.418 mol Ca(ClO₃)₂ *
= 1.254 mol O₂
Finally we <u>convert O₂ moles into grams</u>:
- 1.25 mol O₂ * 32 g/mol = 40.1 g O₂