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Aleks04 [339]
3 years ago
5

The pressure of a certain amount of gas in a 1.25 L balloon is 760 torr. What would the pressure of that balloon be if it's volu

me was increased to 2.15 L?
Chemistry
1 answer:
insens350 [35]3 years ago
5 0
<h3>Answer:</h3>

440 torr

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Ideal Gas Law</u>

Boyle's Law: P₁V₁ = P₂V₂

  • P₁ is pressure
  • V₁ is volume
  • P₂ is new pressure
  • V₂ is new volume

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>
<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify</em>

[Given] V₁ = 1.25 L

[Given] P₁ = 760 torr

[Given] V₂ = 2.15 L

[Solve] P₂

<u>Step 2: Solve for </u><em><u>P₂</u></em>

  1. Substitute in variables [Boyle's Law]:                                                              (760 torr)(1.25 L) = P₂(2.15 L)
  2. Multiply:                                                                                                             950 torr · L = P₂(2.15 L)
  3. [Division Property of Equality] Divide 2.15 L on both sides:                          441.86 torr = P₂
  4. Rewrite:                                                                                                             P₂ = 441.86 torr

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

441.86 torr ≈ 440 torr

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