Answer:
Burning a match
Explanation:
A chemical change is where a substance is changed into one or more substances. Basically, a chemical change changes the form of a substance. While, a physical change such as ripping a piece of paper in half will still be a paper just in half(nothing is changed).
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Answer:
1
Explanation:
if 33 the answer would be 92 but u think then 92 32 1
I am unsure if this is correct, but this might be the whole section:
- The top of the syringe is a circle. You need to compute its area for use in later computations of pressure values. Start by using a ruler to measure the diameter. Estimate to the nearest 0.01 cm. <em>Answer: </em><em>3.60 </em><em>cm</em>
- Divide by two to find the radius. Maintain significant figures. <em>Answer: </em><em>1.80 </em><em>cm</em>
- Substitute the radius into the formula A = πr² to find the area of the top of the syringe. Maintain significant figures. <em>Answer: </em><em>10.2 </em><em>cm²</em>
Answer:
21.2 gm
Explanation:
calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units
butane is the hydrocarbon C4H10
in combustion, we react hydrocarbons with O2 to form CO2 and H2O
so
C4H10 + O2----------------> CO2 + H2O
BALANCE
2C4H10 + 1302--------> 8CO2 + 10 H2O
the molar mass of CO2 is 12 + 16X2 = 44
64.1 gm of CO2 is
64.1/44 = 1.46 MOLES OF CO2,
FOR EVERY 8 MOLES OF CO2 WE NEED 2 MOLES OF BUTANE IT IS A
8:2 OR 4:1 RATIO. THE MOLES OF C4H10 ARE 1/4 THE MOLES OF CO2
SO
THE MOLES OF C4H10 H10 ARE 1.46/4 =0.365 MOLES
THE MOLAR MASS OF BUTANE IS 58.12
0.365 MOLES OF C4H10 HAS A MASS OF 0.365 X 58.12 = 21.2 gm
Answer:
A
C
Explanation:
For the reaction of m-bromonitrobenzene from benzene first, we need to carry out the nitration of benzene utilizing HNO3, H2SO4.
Bromination of nitrobenzene with Br2, FeBr3 outfits m-bromonitrobenzene in light of the fact that nitro group is meta coordinating for electrophile. The mechanism activity for the reaction is shown in the image below.