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3 years ago

13

Is a relation always a function ? is a function always a relation ? explain

1 answer:

Sunny_sXe [5.5K]3 years ago

3 0

It just so happens that it's always the same y for each x, but it is only that one y. So this is a function; it's just an extremely boring function! ... So this is a relation, but it is not a function.

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PLEASE HELP THANK YOU

poizon [28]

Answer:

money left= -50•games played + 47.50

3 0

2 years ago

Can someone please help me

Daniel [21]

Answer:

(-7.5, 3.5)

Step-by-step explanation:

$midpoint \: = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )$

$= ( \frac{ ( - 5) + ( - 10)}{2} , \frac{(5) + (2)}{2} )$

$= ( \frac{ - 15}{2} , \frac{7}{2} )$

$= ( - 7.5,3.5)$

8 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

4 years ago

Y=r + 5x + 4<br> please help!!!!

frez [133]

Your answer would be R=-5x-4+y

6 0

3 years ago

Click now please i need help with math :D

lisov135 [29]

The answer is fifteen yards

6 0

3 years ago

Read 2 more answers