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Jajaj Josh’s but link.bio hope that helps
Answer:
C
Step-by-step explanation:
This means that there is another leg of an isosceles triangle that is also 5 inches.
a^2 + b^2 = c^2
a = 5
b = 5
c = ?
c^2 = 5^2 + 5^2 Combine
c^2 = 25 + 25
c^2 = 50 Take the square root of both sides.
sqrt(c^2) = sqrt(50^2)
c = sqrt(5 * 5 * 2) Take out 1 of two factors under the root sign.
c = 5 * sqrt(2) The 2 is left over because there is only 1 of them
sqrt(2) = 1.4142
c = 5 * 1.4142
c = 7.07 = 7.1
Answer:
The length of DE is 14 cm.
Step-by-step explanation:
Given in triangle ABC segment DE is parallel to the side AC . (The endpoints of segment DE lie on the sides AB and BC respectively). we have to find the length of DE.
Given lengths are AC=20cm, AB=17cm, and BD=11.9cm
In ΔBDE and ΔBAC
∠BDE=∠BAC (∵Corresponding angles)
∠BED=∠BCA (∵Corresponding angles)
By AA similarity rule, ΔBDE~ΔBAC
∴their corresponding sides are in proportion
⇒
⇒
⇒
⇒
Use the Law of Sines:
600 a
---------- = ---------- where 94 came from subtracting (11 + 75) from 180.
sin 11 sin 94
Solve this for side a.
Factor 6x^4−5x^2+12x^2−10
6x^4+7x^2−10
=(x^2+2)(6x^2−5)
Answer: (x^2+2)(6x^2−5)