Answer and Explanation:
The computation of the service level and the corresponding optimal stocking level is shown below:
Given that
Selling price = SP = $4.50
Cost price = CP = $3.00
So,
Salvage value = V = $1.50
Average daily demand (d) = 35 quarts
The standard deviation of daily demand = 4 quarts
based on the above information
Overage cost = (Co) is
= CP - V
= $3.00 - $1.50
= $1.50
Now
Underage cost= (Cu)
= SP - CP
= $4.50 - $3.00
= $1.50
So,
Service level is
= Cu ÷ (Co + Cu)
= 1.50 ÷ (1.50 + 1.50)
= 1.50 ÷ 3.00
= 0.50
= 50%
Now
At 50 % service level, the value of Z is 0
So,
Optimal stocking level is
= d + Z × standard deviation
= 35 + (0 × 4)
= 35 + 0
= 35 quarts
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Answer:
The cash award will be equal;l to $444422.01
Explanation:
We have given amount invested P = $440000
Rate of interest r = 8.3%
Time t = 1 year
As the amount is compounded on daily basis
We know that 1 year = 365 days
So rate of interest
%
Time period n = 365
We know that final amount is equal to 
So
$
So the cash award will be equal;l to $444422.01
Answer:
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