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ch4aika [34]
3 years ago
12

Please Help. Which of the following statements about wide area networks are true? Select 3 options.

Computers and Technology
1 answer:
Likurg_2 [28]3 years ago
8 0

Answer:

B, D, E

Explanation:

The public Internet is largest WAN in the world.

A LAN (Local Area Network) typically uses Ethernet and Wireless Routers to connect devices.

A single business would not usually manage a WAN because this would create a monopoly, which is why competition is intentionally created between Internet Service Providers (ISPs), though sometimes a single business could manage a WAN via MPLS, etc.

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When an important file is saved on two different computers, what is the name of the file that is housed on the second computer?
OleMash [197]
When an important file is saved on two different computers, the name of the file that is housed on the second computer is 'back up'. Back up refers to the process of copying and archiving a particular computer data in order to have an extra copy to fall back on in the event of data loss.  <span />
5 0
3 years ago
Identifying the problem is crucial when trying to solve a problem. There are several techniques that you can use to aide you in
erica [24]
Consensus Building is NOT a technique that you can use to help you in identifying a problem.
8 0
3 years ago
Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
3 years ago
Explain benefits and disadvantages of using BNC over F-Type connectors on coaxial cables
Leokris [45]

Answer:

The benefits and disadvantages of using BNC over F-Type connectors on coaxial cables are;

The <em>benefits </em>of the BNC includes;

1) Easy connect and disconnect for a more rapid connection unlike the F-Type connector which is a screw connector

2) Reduction on stress on the termination of the coaxial cable

3) Appropriate in systems that see frequent reconfiguration unlike te F-Type connector that is permanently attached

4) Prevent unwanted disconnection ensuring image consistency by locking into place

5) Can extend to 300 ft.

The <em>disadvantages</em> of the BNC connectors are;

1) A separate power supply for the cable is required

2) Is used only for video transmission

3) Cannot be used for audio

4) The center wire is not easily visible like those of the F-Type connector which serves as a pin

5) The BNC connector is not watertight like the F-Type connectors

6) There are no provision for properly and securely attaching the cable to the camera for field work such that it can be easily disconnected while in use unlike the F-Type connectors

7) It is not as easy to manufacture like the F-Type connector and it is more expensive

8) The installation of the BNC connector on a coaxial cable is more intricate and the center cable is hidden from view after the BNC is attached thereby making it not possible to see if there is an error in installation which is unlike the F-type connector that takes less than 30 seconds to be attached to a cable

9) The F-Type connector provides more cost savings during installation than the BNC connector

Explanation:

The BNC connector is a type of bayonet connector used more frequently on CCTV systems. The benefits of the BNC includes;

The F-Type connectors are usable on SATV, CATV, and Digital TV where they are used together with RG6 or RG11 cables

3 0
3 years ago
Write a method called findNames that meets the following specs: It takes two arguments: a list of strings, allNames, and a strin
Anna11 [10]

Answer:

public class Solution {

   public static void main(String args[]) {

       String[] allNames = new String[]{"Bob Smith", "Elroy Jetson", "Christina Johnson", "Rachael Baker", "cHRis", "Chris Conly"};

       String searchString = "cHRis";

       

       findNames(allNames, searchString);

   }

   

   public static void findNames(String[] listOfName, String nameToFind){

       ArrayList<String> resultName = new ArrayList<String>();

       

       for(String name : listOfName){

           if (name.toLowerCase().contains(nameToFind.toLowerCase())){

               resultName.add(name);

           }

       }

       

       for(String result : resultName){

           System.out.println(result);

       }

   }

}

Explanation:

The class was created called Solution. The second line define the main function. Inside the main function; we initialized and assign an array called allNames to hold the list of all name. Then a String called searchString was also defined. The searchString is the string to search for in each element of allNames array. The two variables (allNames and searchString) are passed as argument to the findNames method when it is called.

The method findNames is defined and it accept two parameters, an array containing list of names and the name to search for.

Inside the findNames method, we initialized and assigned an ArrayList called resultName. The resultName variable is to hold list of element found that contain the searchString.

The first for-loop goes through the elements in the allNames array and compare it with the searchString. If any element is found containing the searchString; it is added to the resultName variable.

The second for-loop goes through the elements of the resultName array and output it. The output is empty if no element was found added to the resultName variable.

During comparison, the both string were converted to lower case before the comparison because same lowercase character does not equal same uppercase character. For instance 'A' is not same as 'a'.

8 0
3 years ago
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