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3 years ago

Set up the equation for the following word problem and solve the equation. Let y be the unknown number.

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

5 0

Answer

-4y - 67 = y - 17

Step by step explanation

Let y be the unknown number.

-4 times a number minus 67 is equal to 17 less than the number.

The number is y

times means multiplication

-4y - 67 = y - 17

Hope you will understand the concept.

Thank you.

Sergeeva-Olga [200]3 years ago

3 0

<u>Answer:</u>

-4y - 67 = y - 17

<u>Step-by-step explanation:</u>

We are given y to be assumed as the unknown number here in this word problem.

So we will establish the equation step by step.

-4 times a number: the number y is multiplied by -4 to give -4y

minus 67: 67 is subtracted from -4x to give -4y - 67

is equal to 17 less than the number: it means that half of the already constructed equation is equal to y - 17

so the full equation will be:

-4y - 67 = y - 17

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Answer:

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Step-by-step explanation:

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3 years ago

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ANTONII [103]

Answer:

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Step-by-step explanation:

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2 years ago

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Dennis decided he wanted to go to the carnival. The carnival charges $6.00 for entry and $1.50 for each ride.

myrzilka [38]

We want to create a linear equation to model the given situation.

A) c(r) = $6.00 + $1.50*r

B) 19 rides.

We know that the carnival charges $6.00 for entry plus $1.50 for each ride.

A) With the given information we can see that if you ride for r rides, then the cost equation will be:

c(r) = $6.00 + $1.50*r

Where c(r) is the cost for going to the carnival and doing r rides.

B) If you have $35.00, then we can solve:

c(r) = $35.00 = $6.00 + $1.50*r

Now we can solve the equation for r.

$35.00 = $6.00 + $1.50*r

$35.00 - $6.00 = $1.50*r

$29.00 = $1.50*r

$29.00/$1.50 = r = 19.33

Rounding to the next whole number we get: r = 19

This means that with $35.00, Dennis could go to 19 rides.

If you want to learn more, you can read:

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2 years ago

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3 years ago

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Problem1 The behavior of a physical system can be described by the following first order differential equation: dy/dt=2y +t^2

daser333 [38]

Answer:

$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$ .

Step-by-step explanation:

Using first order linear differential equation:

$\dfrac{\mathrm{d} y}{\mathrm{d} t} = 2y + t^2$

$\frac{\mathrm{d} y}{\mathrm{d} t} - 2y =t^2$

finding integrating factor:

I.F = $e^{\int -2dt}$

I.F = $e^{-2t}$

now,

$y = \dfrac{1}{IF}(\int t^2dt+ c )$

$y = \dfrac{1}{e^{-2t}}(\int t^2dt+ c )$

$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$

hence the solution is

$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$

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3 years ago