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Veseljchak [2.6K]
3 years ago
11

I need this answered asap !

Mathematics
2 answers:
defon3 years ago
8 0

Answer:

week 16

Step-by-step explanation:

gtnhenbr [62]3 years ago
4 0

Answer:

Week 16

Step-by-step explanation:

Week 1: 3.5 miles  => 22.5 miles left

22.5/1.5 increments = 15 weeks

15 weeks + week 1 = 16th week

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Please help and thank you
Lorico [155]

Answer:

B. g(x) = (x + 4)²

Step-by-step explanation:

f(x) = x²

And since graph g(x) is f(x) moved 4 points along x-axis and to the right,

g(x) will be equal to (x + 4)²

g(x) = (x + 4)²

4 0
3 years ago
I suck at math. help me. i would app it.
Verizon [17]

Answer:

x= 2

Step-by-step explanation:

y = 7 means it is parallel to the x axis . so the perpendicular line is to be parallel yo the y axis. .

so the equation is to be like x = c

but it is passing (2,13)

so the equation is

x= 2

3 0
2 years ago
Perimeter of this shape
motikmotik

Answer:

22 cm

Step-by-step explanation:

Simply count the number of square units of each side, then add them up. (each square unit = 1 cm)

4+4+2+3+2+7

= 22 cm

6 0
2 years ago
Read 2 more answers
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
I know the answer is 12, but why?
Gala2k [10]
(fog)(2)=f(g(2))

so first evaluate g(2)
we know that g(2)=7
then now we evaluate f(7)
answer is 12

see
f(g(2))=f(7)=12
7 0
3 years ago
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