The complete sentence is the following:
<span>" As the size of the nucleus increases, more NEUTRONS are needed to maintain the attractive force. "
In fact, as the size of the nucleus increases and the number of protons increases, the repulsive electrostatic forces between them increase as well (because the protons have the same electric charge, so they repel each other). In order to hold them together, it is necessary to have more neutrons in the nucleus. In fact, the strong nuclear force acts between protons and neutrons holding them together, like a "glue", and preventing the nucleus from breaking apart due to the repulsive electrostatic force of the protons.</span>
Answer:
What type of question is this?
Explanation:
Is this a true or false question?
We have: K.E. = 1/2 mv²
Here: m = 3 Kg
v = 6 m/s
Substitute their values,
K.E. = 1/2 * 3 * 6²
K.E. = 1/2 * 3 * 36
K.E. = 54 J
In short, Your Answer would be 54 Joules
Hope this helps!
Answer:
No, the distance from the last stop to the school and the time it takes to travel that distance are required.
Answer:
6858.5712 m/s
Explanation:
Given that:
Radius, r
R = 3.20 * 10^3.
Normal force = 0.5 * normal weight
Normal force = Fn ; Normal weight = Fg
Fn = 0.5Fg
Recall:
mv² / R = Fn + Fg
Fn = 0.5Fg
mv² / R = 0.5Fg + Fg
mv² /R = 1.5Fg
mv² = 1.5Fg * R
F = mg
mv² = 1.5* mg * R
v² = 1.5gR
v = sqrt(1.5gR)
V = sqrt(1.5 * 9.8 * 3.2 * 10^3)
V = sqrt(47.04^3)
V = 6858.5712 m/s
