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Alex73 [517]
3 years ago
13

Which of these is the universal law of gravitation? All matter is attracted and pulled downward toward the ground. Most matter i

s attracted and pulled downward toward the ground. Only surface matter is attracted and pulled downward toward the ground.
Physics
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

The answer to your question is: The first option is correct.

Explanation:

All matter is attracted and pulled downward toward the ground.

Most matter is attracted and pulled downward toward the ground. This option is incorrect, because all matter is attracted and pulled downward the ground.

Only surface matter is attracted and pulled downward toward the ground.

Only surface matter is incorrect, all matter is attracted and pulled downward.

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You observe that a mass suspended by a spring takes 0.25 s to make a full oscillation. What is the frequency of this oscillation
Katarina [22]

Answer:

Frequency of oscillation, f = 4 Hz

time period, T = 0.25 s

Angular frequency, \omega = 25.13 rad/s

Given:

Time taken to make one oscillation, T = 0.25 s

Solution:

Frequency, f of oscillation is given as the reciprocal of time taken for one oscillation and is given by:

f = \frac{1}{T}

f = \frac{1}{0.25}

Frequency of oscillation, f = 4 Hz

The period of oscillation can be defined as the time taken by the suspended mass for completion of one oscillation.

Therefore, time period, T = 0.25 s

Angular frequency of oscillation is given by:

\omega = 2\pi \times f

\omega = 2\pi \times 4

\omega = 25.13 rad/s

5 0
3 years ago
Air bags are designed to deploy in 10 ms. Given that the air bags expand 20 cm as they deploy, estimate the acceleration of the
joja [24]

As it is given that the air bag deploy in time

t = 10 ms = 0.010 s

total distance moved by the front face of the bag

d = 20 cm = 0.20 m

Now we will use kinematics to find the acceleration

d = v_i*t + \frac{1}{2}at^2

0.20 = 0 + \frac{1}{2}a*0.010^2

0.20 = 5 * 10^{-5}* a

a = 4000 m/s^2

now as we know that

g = 10 m/s^2

so we have

a = 400g

so the acceleration is 400g for the front surface of balloon

3 0
3 years ago
A 20.0-kg block is initially at rest on a horizontal surface. A horizontal force of 77.0 N is required to set the block in motio
saveliy_v [14]

Answer: The coefficient of static friction is 3.85 and  The coefficient of kinetic friction is 2.8

Explanation:

in the attachment

6 0
3 years ago
What material are you most likely to find in the D horizon
statuscvo [17]

you're most likely to find Bedrock

7 0
3 years ago
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A high jumper jumps over a bar that is 2 m above the mat. With what velocity does the jumper strike the mat in the landing area?
docker41 [41]

Answer:

The velocity with which the jumper strike the mat in the landing area is 6.26 m/s.

Explanation:

It is given that,

A high jumper jumps over a bar that is 2 m above the mat, h = 2 m

We need to find the velocity with which the jumper strike the mat in the landing area. It is a case of conservation of energy. let v is the velocity. it is given by :

v=\sqrt{2gh}

g is acceleration due to gravity

v=\sqrt{2\times 9.81\ m/s^2\times 2\ m}

v = 6.26 m/s

So, the velocity with which the jumper strike the mat in the landing area is 6.26 m/s. Hence, this is the required solution.

8 0
3 years ago
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