I don’t know the answer for a and b. I’m really sorry.
C) 24 more
D) 18 more hours
Answer:
The speed and time are directly proportional in that the higher the speed the lesser the time and vice versa.
The constant is the total distance which is 180 km
Step-by-step explanation:
Step one:
given data
The distance between the two cities is 180km
1.The distance was covered by a car at the rate of 50km/h
The time taken will be
velocity= distance/time
time= distance/velocity
time= 180/50
time= 3.6 hours
2.The distance was covered by a bus 45km/h
The time taken will be
velocity= distance/time
time= distance/velocity
time= 180/45
time= 4 hours
3.The distance was covered by a bicycle at 25km/h
The time taken will be
velocity= distance/time
time= distance/velocity
time= 180/25
time= 7.2 hours
6x + 4y = 12...subtract 6x from both sides
4y = -6x + 12 ...divide both sides by 4
(4/4)y = (-6/4)x + 12/4...reduce
y = -3/2x + 4 <== y = mx + b
Answer:
(I) (-5) is a zero of P(x)
(II) 5 is a zero of P(x)
(III) (-5/2) is a zero of P(x)
Step-by-step explanation:
<h3>
(I) P(x) = x + 5</h3>
Here, P(x) = x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ x + 5 = 0
∴ x = (-5)
Thus, (-5) is a zero of P(x)
<h3>(II) P(x) = x - 5</h3>
Here, P(x) = x - 5
To find the zeroes of P(x)
let P(x) = 0
∴ x - 5 = 0
∴ x = 5
Thus, 5 is a zero of P(x)
<h3>(III) P(x) = 2x + 5</h3>
Here, P(x) = 2x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ 2x + 5 = 0
∴ 2x = -5
∴ x = (-5/2)
Thus, (-5/2) is a zero of P(x)
<u>-</u><u>TheUnknownScientist</u>
We'll need to find the 1st and 2nd derivatives of F(x) to answer that question.
F '(x) = -4x^3 - 27x^2 - 48x - 16 You must set this = to 0 and solve for the
roots (which we call "critical values).
F "(x) = -12x^2 - 54x - 48
Now suppose you've found the 3 critical values. We use the 2nd derivative to determine which of these is associated with a max or min of the function F(x).
Just supposing that 4 were a critical value, we ask whether or not we have a max or min of F(x) there:
F "(x) = -12x^2 - 54x - 48 becomes F "(4) = -12(4)^2 - 54(4)
= -192 - 216
Because F "(4) is negative, the graph of the given
function opens down at x=4, and so we have a
relative max there. (Remember that "4" is only
an example, and that you must find all three
critical values and then test each one in F "(x).
