Igneous rocks are formed from solidification and cooling of magma. The magma can be obtanied from partial melts of pre-existing rocks in either the planet's mantle or crust. Plutonic or intrusive rocks area result of when the magma cools and crystallizes slowly within the Earth's crust. A example is granite.
Answer:
The length of her shadow is changing at the rate -2 m/s
Explanation:
Let the height oh the street light, h = 22 ft
Let the height of the woman, w = 5.5 ft
Horizontal distance to the street light = l
length of shadow = x
h/w = (l + x)/x
22/5.5 = (l + x)/x
4x = l + x
3x = l
x = 1/3 l
taking the derivative with respect to t of both sides
dx/dt = 1/3 dl/dt
dl/dt = -6 ft/sec ( since the woman is walking towards the street light, the value of l is decreasing with time)
dx/dt = 1/3 * (-6)
dx/dt = -2 m/s
<span>A cart travels down a ramp at an average speed of 5.00
centimeters/second. What is the speed of the cart in miles/hour? </span>
To solve this problem we have set the conversion values to
determine the product during the conversion process.
<span><span>
1. </span>1
centimeter = 0.00000621371 mile</span>
<span><span>
2. </span><span> 1 hour = 60 minutes</span></span>
<span><span>3. </span><span> 1 minute = 60 seconds</span></span>
Thus, we shall have
<span><span>1. </span>5 cm x 0.00000621371
mile/1cm = 0.000031069 mi</span>
<span><span>2. </span>0.000031069
seconds x 1 hr / 3600 = 0.111846815 miles / hr</span>
Answer:
15.8m/s
Explanation:
This problem can be solved by taking into account the conservation of the momentum. In this case the momentum of the astronaut and the bag of tools must equal the momentum of the astronaut and the bag of tool after the astronaut throws the bag.
Hence, we have
where ma and va are the mass and velocity of the astronaut, mb and vb are the mass and velocity of the bag, after the astronaut throw the bag. The velocity v is the velocity where the astronaut has the bag of tool
By taking into account that the velocity of the astronaut must be zero to keep him near of the space station, we have that vb = 0.
Thus
Answer:
(a) 34.4°
(b) 49.4 N
Explanation:
(a) From the diagram,
Amgle between the x axis can be calculated as,
cosΘ = adjacent/hypoteneous
cosΘ = 72.1/87.4
cosΘ = 0.8249
Θ = cos⁻¹(0.8249)
Θ = 34.4°.
Hence the angle between the x axis is 34.4°
(b) To find the component along the y axis we make use of pythagoras theorem.
a² = b²+c²................... Equation 1
Where a = 87.4 N, b = 72.1 N, c = y.
Substitute these values into equation 1
87.4² = 72.1² + y²
y² = 87.4²-72.1²
y² = 2440.35
y = √(2440.35)
y = 49.4 N
