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4 years ago

Describe the type of rock and it’s texture that would form from the melted meteorite and Earths rocks

1 answer:

8 0

Igneous rocks are formed from solidification and cooling of magma. The magma can be obtanied from partial melts of pre-existing rocks in either the planet's mantle or crust. Plutonic or intrusive rocks area result of when the magma cools and crystallizes slowly within the Earth's crust. A example is granite.

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Which of the following non-metals is used as a lubricant in powdered form?

blondinia [14]

Answer:

Graphite.

Explanation:

Graphite:<em> "a gray crystalline allotropic form of carbon which occurs as a mineral in some rocks and can be made from coke. It is used as a solid lubricant, in pencils, and as a moderator in nuclear reactors."</em>

5 0

3 years ago

g A hydraulic press has a safety feature which consists of a hydraulic cylinder with a piston at one end and a safety valve at t

nlexa [21]

Answer:

58.32 N

Explanation:

Area of a circle = $\pi$ $r^{2}$

where r is the radius of the circle.

The cylinder has a radius of 0.02 m, its area is;

$A_{1}$ = $\pi$ $r^{2}$

= $\frac{22}{7}$ x $(0.02)^{2}$

= $\frac{22}{7}$ x 0.0004

= 1.2571 x $10^{-3}$

Area of the cylinder is 0.0013 $m^{2}$ .

The safety valve has a radius of 0.0075 m, its area is;

$A_{2}$ = $\pi$ $r^{2}$

= $\frac{22}{7}$ x $(0.0075)^{2}$

= $\frac{22}{7}$ x 5.625 x $10^{-5}$

= 1.7679 x $10^{-4}$

Area of the valve is 0.00018 $m^{2}$ .

From Hooke's law, the force on the safety valve can be determined by;

F = ke

$F_{2}$ = 950 x 0.0085

= 8.075 N

Minimum force, $F_{1}$ , required can be determined by;

$\frac{F_{1} }{A_{1} }$ = $\frac{F_{2} }{A_{2} }$

$\frac{F_{1} }{0.0013}$ = $\frac{8.075}{0.00018}$

$F_{1}$ = $\frac{0.0013 *8.075}{0.00018}$

= 58.32

The minimum force that must be exerted on the piston is 58.32 N.

8 0

3 years ago

There are billions of stars in the universe how are they classified

Ilia_Sergeevich [38]

Answer: In 1926, an astronomer named Edwin Hubble decided to classify the galaxies, grouping them according to some logical scheme.

Explanation:

8 0

4 years ago

An elevator weighing 2.00 x 10 5 N is supported by a steel cable. What is the tension in the cable when the elevator is accelera

STALIN [3.7K]

First, we will get the mass of the elevator:
Fw = mass * gravitational acceleration
2 * 10^5 = mass * 9.8
mass = 20.4 * 10^3 kg

Now, the total force acting on the elevator can be written as follows:
Fnet = Tension - Fw
mass * acceleration = Tension - 2*10^5
20.4 * 10^3 * 3 = Tension - 2*10^5
61200 = Tension - 2*10^5
Tension = (61200) + (2*10^5)
Tension = 2.61 * 10^5 newton

6 0

3 years ago

Calculate the magnitude of the following vector components in OX and OY directions

12345 [234]

Answer:

Very easy question

For x-component, we use Fₓ = Fcosα

For y-component, we use Fy = Fsinα

The major problem is with angle α.

Here α = 90+30

Because the angle is measured from +ve X-axis.

By putting values if you know co-ratios that how Sin and cos Convert to each other then you have got it.

So for further calculation,

Fₓ = Fcos(90+30) = 25(-sin30)

Fₓ = -25(1/2) = 25/2 = 12.5 - will be eliminate because force in magnitude is not "-ve"

As it is

Fy = Fsin(90+30) = Fcos30

Fy = 25 (√3 /2) = 25√3/2

......................................................................................

3 0

3 years ago