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11Alexandr11 [23.1K]
3 years ago
15

Popcorn was donated for the school fair by 3 different popcorn vendors they donated a total of 636 bags of popcorn each vendor d

onated the same number of bags how many bags of popcorn did each vendor donate
Mathematics
1 answer:
Nitella [24]3 years ago
5 0

Answer: 212


Step-by-step explanation:

Divide 636 by 3

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2 years ago
Find the missing side
lisabon 2012 [21]

Answer: 1) The missing length is 40.   2) The missing side is 30 .

Step-by-step explanation:

1)  9^2  + b^2 = 41^2

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   -81                   -81

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5 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
Please help! 11 pts.
Veronika [31]

The Pythagorean theorem formula for a triangle is A^2 + B^2 = C^2 where A and B are the sides and C is the hypotenuse.

The sides of the triangle shown are AB and BC and the hypotenuse is AC,

so the correct answer would be:

(AB)2 + (BC)2 = (AC)2, because 25 + 144 = 169

3 0
3 years ago
Read 2 more answers
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