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Nikolay [14]
3 years ago
11

EXPLAIN HOW I NEED HELP

Mathematics
2 answers:
babymother [125]3 years ago
8 0

Answer:

The answer is x=13

Step-by-step explanation:

X=13 because when you simplify 16/6 it will equal 8/3 which is what you are trying to figure out what they had to get that.

dsp733 years ago
3 0

Answer:

x = 13

Step-by-step explanation:

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Help me plsssssssssssss
san4es73 [151]

Answer:

3/1/4

That's the expression represents Lena's speed in miles per hour

4 0
2 years ago
What are all solutions to the differential equation dy/dx=sec^2*x ?
zysi [14]

Answer:

y=tanx+C

Step-by-step explanation:

\frac{dy}{dx}  =  {sec}^{2}  \: x \\  \\ dy = {sec}^{2}  \: x \: dx \\  integrating \: both \: sides \\  \\  \int \:1\: dy =  \int {sec}^{2}  \: x \: dx \\  \\  \huge \red{ \boxed{ \therefore \: y = tan \: x + c}} \\

4 0
3 years ago
The table below shows the radius y, in inches, created by growing algae in x days: Time (x) (days) 1 4 7 10 Radius (y) (inches)
tatuchka [14]
PART A:
Given the table below showing the radius y, in inches, created by growing algae in x days.

Time (x) (days):          1       4        7        10
Radius (y) (inches):    1       8       11       12

We can find the find the correlation coeficient of the data using the table below:
\begin{center}
\begin{tabular}
{|c|c|c|c|c|}
x & y & x^2 & y^2 & xy \\ [1ex]
1 & 1 & 1 & 1 & 1\\
4 & 8 & 16 & 64 & 32\\
7 & 11 & 49 & 121 & 77\\
10 & 12 & 100 & 144 & 120\\ [1ex]
\Sigma x=22 & \Sigma y=32 & \Sigma x^2=166 & \Sigma y^2=330 & \Sigma xy=230
\end{tabular}
\end{center}

Recall that the correlation coefitient is given by the equation:
r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{ \sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)} }  \\  \\ = \frac{4(230)-(22)(32)}{ \sqrt{(4(166)-(22)^2)(4(330)-(32)^2)} } = \frac{920-704}{ \sqrt{(664-484)(1,320-1,024)}}  \\  \\ = \frac{216}{ \sqrt{180(296)}} = \frac{216}{ \sqrt{53,280} } = \frac{216}{230.8} =0.94

[Notice: even without using the formular to find the value of the correlation coeficient, it can be seen that the value of y strictly increases as the valu of x increases. This means that the value of the correlation coeficient is closer to +1 and from the options the value that is closest to +1 is 0.94]

From the value of the correlation coeffeicient, it can be deduced that the radius of the algae has a strong positive relationship with the time.

Recall the for the value of the correlation coeficient closer to +1, the relationship is strong positive, for the value closer to -1, the value is strong negative and for the values closer to zero, either way of zero is a weak positive if it is positive and weak negative if it is negative.


PART B:
Recall that the slope of a straight line passing through two points
(x_1,y_1) and (x_2,y_2)
is given by
m= \frac{y_2-y_1}{x_2-x_1}

Thus the slope of the graph of radius versus time between 4 and 7 days, [i.e. the line passes through points (4, 8) and (7, 11)] is given by
m= \frac{11-8}{7-4}= \frac{3}{3} =1

The value of the slope means that the radius of the algea grows by 1 inch evry day between day 4 and day 7.


PART C:
We can say that the data above represent both correlation and causationg.

Recall that correlation expresses the relationship between two variables while causation expresses that an event is as a result of another event.

From the information above, we have seen that there is a relationship (correlation) between the passing of days and the growth in the radius of the algae.

Also we can conclude that the growth in the radius of algae is a function of the passing of days, i.e. the growth in the radius of algae is as a result of the passing of days.

Therefore, <span>the data in the table represent both correlation and causation.</span>
6 0
3 years ago
Cindy has four more than five times as many cousins as Kathy, k. which expression represents 1how many cousins Cindy has compare
Nadusha1986 [10]

Hello!

We can write this expression below.

5k+4

I hope this helps!

5 0
4 years ago
Read 2 more answers
Given: ΔABC is a right triangle. Prove: a2 + b2 = c2 The following two-column proof with missing justifications proves the Pytha
Anestetic [448]

Answer:

Transitive property of equality is not a justification for the proof.

Step-by-step explanation:

We draw a right angle ΔACB. CD is perpendicular to AB.

Let AC = a , BC = b , AB = c and CD = h

Now in ΔABC and ΔACD

∠C = ∠D and ∠A = ∠A

from AA similarity postulate

ΔABC  similar to ΔACD.

Hence,

           \frac{c}{a} = \frac{a}{x}

           a^{2} = c × x ·····················(1)

Now in ΔABC and ΔCBD

∠C = ∠D and ∠B = ∠B

from AA similarity postulates

ΔABC similar to ΔCBD

Hence,

           \frac{c}{b} = \frac{b}{y}

           b^{2} = c × y······················(2)

Add equation (1) and (2)

      a^{2} + b^{2} = cx + cy

      a^{2} + b^{2} = c(x+y)

      a^{2} + b^{2} = c^{2}               [because x+y=c]

Transitive property is not useful for this proof.

5 0
3 years ago
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