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-BARSIC- [3]
3 years ago
13

What are all solutions to the differential equation dy/dx=sec^2*x ?

Mathematics
1 answer:
zysi [14]3 years ago
4 0

Answer:

y=tanx+C

Step-by-step explanation:

\frac{dy}{dx}  =  {sec}^{2}  \: x \\  \\ dy = {sec}^{2}  \: x \: dx \\  integrating \: both \: sides \\  \\  \int \:1\: dy =  \int {sec}^{2}  \: x \: dx \\  \\  \huge \red{ \boxed{ \therefore \: y = tan \: x + c}} \\

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What is 78.74 rounded to the nearest tenth?
sveticcg [70]

Answer:

The answer is <u>80</u>

Step-by-step explanation:

78.74 is closer to 80 than it is to 70.


4 0
3 years ago
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A boat costs $8,350 and decreases in value by 12% per year. how much will the boat be worth after 5 years?
BARSIC [14]
The boat would cost 3,340 dollars
7 0
3 years ago
Which statement is true about the equation 22-2=m-7?
Liono4ka [1.6K]
22-2=m-7.
first you subtract 22-2 thats 20.
then youtake 20 and subtract it by 7 but in order to do that you have to make 20 negative.
 m-7
-    20
this equals m-20
4 0
3 years ago
Plz prove this for me.....
s344n2d4d5 [400]

I've answered your other question as well.

Step-by-step explanation:

Since the identity is true whether the angle x is measured in degrees, radians, gradians (indeed, anything else you care to concoct), I’ll omit the ‘degrees’ sign.

Using the binomial theorem, (a+b)3=a3+3a2b+3ab2+b3

⇒a3+b3=(a+b)3−3a2b−3ab2=(a+b)3−3(a+b)ab

Substituting a=sin2(x) and b=cos2(x), we have:

sin6(x)+cos6(x)=(sin2(x)+cos2(x))3−3(sin2(x)+cos2(x))sin2(x)cos2(x)

Using the trigonometric identity cos2(x)+sin2(x)=1, your expression simplifies to:

sin6(x)+cos6(x)=1−3sin2(x)cos2(x)

From the double angle formula for the sine function, sin(2x)=2sin(x)cos(x)⇒sin(x)cos(x)=0.5sin(2x)

Meaning the expression can be rewritten as:

sin6(x)+cos6(x)=1−0.75sin2(2x)=1−34sin2(2x)

3 0
3 years ago
PLEASE HELP ME
lyudmila [28]
As seen, the graph is pointing/increasing upwards. This means that the graph is exponentially increasing. 

You notice there are significantly more spores at 4th hour than the first, therefore, this is an increasing trend. 

Hope I helped :) 
6 0
3 years ago
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