What are all solutions to the differential equation dy/dx=sec^2*x ?

Elodia [21]

You can split the combined shape into separate shapes and find the area of each of those. once you have done that add all of the areas together and that will get you your combined shapes area.

3 0

3 years ago

What is an equation of the line that passes through the points (-1, 6) and<br> (-1, -5)?

kobusy [5.1K]

Answer:

x = -1

Step-by-step explanation:

(-1 , 6) ; (-1 , -5)

There is no change in x-coordinate values.

So, the is parallel to y-axis

x = -1

4 0

2 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

(28 and 29) I really need help

scoundrel [369]

Answer:

28 is 11/60

29 is 7/30

Step-by-step explanation:

5 0

3 years ago

Please help ASAP!!!

QveST [7]

The answer is 3. 1/6 because there are 6 sides in the cube. So the probability of getting a certain number is 1/6.

7 0

3 years ago