9514 1404 393
Answer:
(x, y) = (1, -5)
Step-by-step explanation:
Using a graphing calculator to solve equations such as these is quick and easy. It is one of my favorite methods. The attached graph shows the solution is ...
(x, y) = (1, -5)
Answer: 800 feet²
Step-by-step explanation:
Lets remove the brackets from the function's expression
A(x) = -2x²+80x
So we got the quadratic function and we have to find the x that corresponds to function's maximum. Let it be X max
As we know Xmax= (X1+X2)/2 , where X1 and X2 are the roots of the function A(x)
Lets find X1 and X2
x(80-2x)=0
x1=0 80-2*X2=0
x2=40
So Xmax= (0+40)/2=20
So Amax= A(20)= 20*(80-2*20)=20*40=800 feet²
Answer:
24 x y
Step-by-step explanation:
Simplify the following:
3×4×2 x y
Hint: | Multiply 3 and 4 together.
3×4 = 12:
12×2 x y
Hint: | Multiply 12 and 2 together.
12×2 = 24:
Answer: 24 x y
Answer:
6
Step-by-step explanation:
6(6 + 1) + 3 = 45
Distribute the parentheses so 36 + 6
36 +6 + 3 = 45
let's notice something, the parabola is a vertical one, so the squared variable is the x, and is opening downwards, meaning the x² will have a negative coefficient.
the distance from the vertex to the directrix/focus is the amount of "p" units, let's see in the graph, the distance from the vertex to the directrix is 2, and since the parabola is opening downwards, "p" is a negative 2, p = -2. The vertex is of course at (0, 2).
![\bf \textit{parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=0\\ k=2\\ p=-2 \end{cases}\implies 4(-2)(y-2)=(x-0)^2\implies -8(y-2)=x^2 \\\\\\ y-2=\cfrac{x^2}{-8}\implies \blacktriangleright y=-\cfrac{1}{8}x^2+2 \blacktriangleleft](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Bparabola%20vertex%20form%20with%20focus%20point%20distance%7D%0A%5C%5C%5C%5C%0A4p%28y-%20k%29%3D%28x-%20h%29%5E2%0A%5Cqquad%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Avertex%5C%20%28%20h%2C%20k%29%5C%5C%5C%5C%20%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%0A%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Cbegin%7Bcases%7D%0Ah%3D0%5C%5C%0Ak%3D2%5C%5C%0Ap%3D-2%0A%5Cend%7Bcases%7D%5Cimplies%204%28-2%29%28y-2%29%3D%28x-0%29%5E2%5Cimplies%20-8%28y-2%29%3Dx%5E2%0A%5C%5C%5C%5C%5C%5C%0Ay-2%3D%5Ccfrac%7Bx%5E2%7D%7B-8%7D%5Cimplies%20%5Cblacktriangleright%20y%3D-%5Ccfrac%7B1%7D%7B8%7Dx%5E2%2B2%20%5Cblacktriangleleft%20)