crosses x-axis at (2, 0 ) and y-axis at (0, - 4 )
To find where the graph crosses the x and y axes ( intercepts )
• let x = 0, in the equation for y- intercept
• let y = 0, in the equation for x- intercept
x = 0 : y = 0 - 4 = - 4 ⇒ (0, - 4 )
y = 0 : 2x - 4 = 0 ⇒ 2x = 4 ⇒ x = 2 ⇒ (2, 0 )
Answer:
-16
Step-by-step explanation:
hope this helps love <3
Answer:
2nd option
Step-by-step explanation:
The shaded area = outside area - inner area
= x² - (x - 6)² ← expand using FOIL
= x² - (x² - 12x + 36) ← distribute parenthesis by - 1
= x² - x² + 12x - 36 ← collect like terms
= 12x - 36
The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
Answer:
Step-by-step explanation:
Each child received two pieces.
So total pieces received by 4 children = 4*2 = 8
Total pieces = 10 + 8 = 18
