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Alex17521 [72]
3 years ago
7

Helpp:)))) PLS

Mathematics
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:

=

Step-by-step explanation:

Because |-4| is basically 4 since its the absolute value of that..

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2. A varies directly as b. If A = 3 when b = 24, find b when A = 10.
Debora [2.8K]
Should be 55 because they are inversely with x
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4 years ago
Plz help me well mark brainliest!
prohojiy [21]

Answer:

9:59

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How to take derivative of absolute value.
zhenek [66]

The absolute value function is defined as

|x| = \begin{cases}x & \text{for }x \ge 0 \\ -x & \text{for }x < 0\end{cases}

If x is strictly positive (x > 0), then |x| = x, and d|x|/dx = dx/dx = 1.

If x is strictly negative (x < 0), then |x| = -x, and d|x|/dx = d(-x)/dx = -1.

But if x = 0, the derivative doesn't exist!

In order for the derivative of a function f(x) to exist at x = c, the limit

\displaystyle \lim_{x\to c}\frac{f(x) - f(c)}{x-c}

must exist. This limit does not exist for f(x) = |x| and c = 0 because the value of the limit depends on which way x approaches 0.

If x approaches 0 from below (so x < 0), we have

\displaystyle \lim_{x\to 0^-}\frac{|x|}x = \lim_{x\to0^-}-\frac xx = -1

whereas if x approaches 0 from above (so x > 0), we have

\displaystyle \lim_{x\to 0^+}\frac{|x|}x = \lim_{x\to0^+}\frac xx = 1

But 1 ≠ -1, so the limit and hence derivative doesn't exist at x = 0.

Putting everything together, you can define the derivative of |x| as

\dfrac{d|x|}{dx} =  \begin{cases}1 & \text{for } x > 0 \\ \text{unde fined} & \text{for }x = 0 \\ -1  & \text{for }x < 0 \end{cases}

6 0
3 years ago
What’s the slope of the line ? please help
DaniilM [7]

Answer: -2/1 is the slope

Step-by-step explanation: hope this helps<3

5 0
3 years ago
The area of the rectangle in the figure is 24a2b3 square units. FIND the width of the rectangle
KonstantinChe [14]
I believe that the answer to this question would be 2(12a + b^3). Wait for someone else for clarification. :)
5 0
4 years ago
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