Question

The sum of three consecutive even integers is 36 . find the smallest of them​

Answer 1

Answer:

10

Step-by-step explanation:

You can get the three consecutive integers by using algebraic expressions.

Let's solve.

Let x be the smallest even integer.

Let x+2 be the second even integer.

Let x+4 be the largest even integer.

• x+x+2+x+4 = 36

• 3x+6 = 36

• 3x = 36-6

• 3x = 30

• x = $\frac{30}{3}$

• x = 10

Therefore, 10 is the smallest even integer.

x+2 = 10+2 = 12

The second even integer is 12.

x+4 = 10+4 = 14

The largest even integer is 14.

Let's check by adding the three even integers.

10+12+14 = 36

36 = 36

It's correct.