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erastova [34]
3 years ago
6

The sum of 3 consecutive odd integers is 39. what are the integers?

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0
Suppose the first odd integer is x, the next one will be x+2, the third one will be x+4
add up these three integers, you will have 3x+6=39
3x=33
x=11
the three consecutive odd integers are 11,13,15
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The area of a rectangle is 44 square units. Its length measures 4 units. Find the length of its diagonal. Round to the nearest t
NikAS [45]

Answer:

√(137)

Step-by-step explanation:

First, you will need to find the other side length.....then you can use the Pythagorean Theorem to find the diagonal:

L x W = 44

4 x W = 44

W =11

Now the Pythag, Theorem:

 diagonal^2 = 4^2 + 11^2

        d^2 = 16+121

         d^2 = 137

          d = √(137)

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Evaluate the expression 4+x3. When x is 3.<br><br> a. 12<br> b. 36<br> c. 31<br> d. 49<br> ??
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Step-by-step explanation:

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3 years ago
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how to determine which quantity is independent and which quantity is dependent when considering a situation
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An easy way to think of independent and dependent variables is, when you're conducting an experiment, the independent variable is what you change, and the dependent variable is what changes because of that. You can also think of the independent variable as the cause and the dependent variable as the effect.

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A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s
Artemon [7]

Answer:

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age  \leq 3}\end{array}\right

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 0 \  \leq  age   \leq  2 }\\{0 \  \leq  age   \leq 3}\end{array}\right]

Also , the age transition matrix is as follows:

L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]

After 1 year ; the age distribution vector will be :

x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]  \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq 1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age   \leq  3}\end{array}\right

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3 years ago
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