Let y = total charge for a car rental and x = miles driven
Proxy car equation: y = 0.32x + 18
YourPal equation: y = 0.36x + 12
Set equations right sides equal to each other... meaning their cost, y, are equal
0.32x + 18 = 0.36x + 12
18 = 0.04x + 12 (subtract 0.32x from both sides of the equation)
6 = 0.04x (subtract 12 from both sides of the equation)
150 = x (divide both sides of the equation by 0.04)
ANSWER: 150 miles
Answer:
3 cars
Step-by-step explanation:
If 12 cars are needed to carry 36 students,
<em>12</em><em>c</em><em>a</em><em>r</em><em>s</em><em> = 36</em>
the number of cars to carry 9 students will be:
xcars = 9
cross the two equations
36x = 12 X 9
36x = 108
x = 108/36
x= 3
Therefore, 3 cars are needed to carry 9 students
OR
12 cars will carry 36 students
so 1 car will carry, (36/12)students
therefore, 1 car will carry 3 students
So, for 9 students,
9students = 9/3 = 3
5=4x+2x-7
5+7=6x
12=6x
12/6=6x/6
2=x
Answer:
x=5
Step-by-step explanation:
4x+10=30
-10 -10 on both sides
4x=20
Divide 4 on both sides
20/4=5
✨Hope this helps!!✨
Answer-44
You can turn both of the denominators ( bottom numbers on the fractions ) into 120 ( the whole number ) and the top numbers can be multiplied by how many times the denominators went into 120. Then add the top numbers which equals 76 and then 120-76=44. Hope that kinda helps !!
