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zmey [24]
3 years ago
7

Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the given lin

e. (4,-2); y=3
Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

y = -1/3x - 2/3

Step-by-step explanation:

y = -1/3x + b

-2 = -1/3(4) + b

-2 = -4/3 + b

-2/3 = b

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6 0
3 years ago
What is the answer to x/6-5=(-13)?
Sophie [7]
Step 1: Simplify both sides of the equation.<span><span><span>x6</span>−5</span>=<span>−13</span></span><span>Simplify: (Show steps)</span><span><span><span><span>16</span>x</span>−5</span>=<span>−13</span></span>Step 2: Add 5 to both sides.<span><span><span><span><span>16</span>x</span>−5</span>+5</span>=<span><span>−13</span>+5</span></span><span><span><span>16</span>x</span>=<span>−8</span></span>Step 3: Multiply both sides by 6.<span>6*<span>(<span>16</span></span></span><span>x)</span>=<span><span>(6)</span>*<span>(<span>−8</span><span>)</span></span></span>x=<span>−<span>48
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7 0
3 years ago
Variables give three possible values for n
Leto [7]


9=1,3,9

3=1,3

the GCF is 3 because the three and one are the only common factors between 3 and 9

 

8 0
3 years ago
Suppose theta= 11pi/12. How do you use the sum identity to find the exact value of sin theta?
SIZIF [17.4K]
The better way is, first we have to find the equivalent in degrees

2\pi=360\º

\frac{11\pi}{12}=345\º

now we can change this value to -15\º

how do we get an angle like this?!

30\º-45\º=-15\º

then

sin(30\º-45\º)=sin(30\º)*cos(45\º)-sin(45\º)*cos(30\º)

\begin{Bmatrix}sin(30\º)&=&\frac{1}{2}\\\\sin(45\º)&=&cos(45\º)&=&\frac{\sqrt{2}}{2}}\end{matrix}\\\\cos(30\º)&=&\frac{\sqrt{3}}{2}\end{matrix}

now we replace this values

sin(-15\º)=\frac{1}{2}*\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}*\frac{\sqrt{3}}{2}

sin(-15\º)=\frac{\sqrt{2}}{4}-\frac{\sqrt{6}}{4}

\boxed{\boxed{sin(-15\º)=sin(345\º)=\frac{\sqrt{2}-\sqrt{6}}{4}}}
4 0
3 years ago
pings ice cream palace offers a special sunday that contains 2 kilograms of ice cream plus any number of toppings. Write an S, t
umka2103 [35]

Let us assume number of toppings = n

Total weight of sundae = s

Quantity of Ice cream = 2 kilograms.

We need to discribe the total weight of the special sundae in kilograms by an inequality.

The sundae contains ice cream and number of toppings. So the total weight of the sundae will be greater than the total weight of ice cream and number of toppings, because there would be some weight of the packing.

Therefore,

The total weight of the sundae > total weight of ice cream + weight of toppings.

s > 2 + n.

Where, s is the total weight of the sundae and n is the weight of toppings.

7 0
3 years ago
Read 2 more answers
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