Ask question

Ask question

All categories

3 years ago

6

n 1990, a music store sold 250 CDs per day. In 1995, they sold 175 CDs per day. Assuming a linear relationship, how many CDs did

the store sell per day in 2000?

1 answer:

gladu [14]3 years ago

8 0

Answer:

100 CD's

Step-by-step explanation:

250-175 is 75. and if yu subtract 175 by 75, you get 100. so 100 CD's

You might be interested in

Find the center and radius of the circle whose equation is x 2 + y 2 + 10x − 1

Margaret [11]

we conclude that the center of the circle is the point (-5, 0).

<h3>How to find the center of the circle equation?</h3>

The equation of a circle with a center (a, b) and a radius R is given by:

$(x - a)^2 + (y - b)^2 = R^2$

Here we are given the equation:

$x^2 + y^2 + 10x - 1 = 0$

Completing squares, we get:

$x^2 + 10x + y^2 = 1$

Now we can add and subtract 25 to get:

$x^2 + 10x + 25 - 25 + y^2 = 1\\\\(x + 5)^2 -25 + y^2 = 1\\\\(x + 5)^2 + (y - 0)^2 = 26$

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).

If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

3 0

2 years ago

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

garri49 [273]

Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = 0.5$ .

Sample of 100, hence $n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05$

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$-2 = \frac{X - 3.5}{0.05}$

$X - 3.5 = -0.1$

$X = 3.4$

Z = 2:

$Z = \frac{X - \mu}{s}$

$2 = \frac{X - 3.5}{0.05}$

$X - 3.5 = 0.1$

$X = 3.6$

The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

7 0

2 years ago

2. Deshay borrowed $400 from the bank for 1 year. The bank charges 14% interest

Papessa [141]

Answer:

The bank charged 56 dollars in interest

7 0

3 years ago

Round 30.410 to nearest hundreth

Oksana_A [137]

The answer to this is 30.41 due to the zero the answer cannot be moved on so it will stay the same.

4 0

3 years ago

Read 2 more answers

In a certain residential suburb, 60% of all households get Internet service from the local cable company, 80% get television ser

Serggg [28]

Answer:

a) 0.900

b) 0.400

Step-by-step explanation:

Let I = households getting internet

T = households getting television

Then I = 60%

and T = 80%

$I\cap T = 50\%$ (Households that get both services)

a) Households getting at least one service, $I\cup T = I + T - I\cap T= 60+80-50 =90\%=0.900$

b) Those getting internet only = $I - I\cap T = 60 - 50 = 10\% = 0.1$

Those getting television only = $T - I\cap T = 80- 50=30\%=0.3$

Probability of getting exactly one service = 0.1 + 0.3 = 0.400

6 0

3 years ago