45.0,
the 4 rounds up to 5 because the 9 is a higher value of 5 or more
Answer:
$1171.05
Step-by-step explanation:
1500 × (1-(6 / 100))⁴
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
We can determine the value of the adult ticket cost and student ticket cost by following these steps:
1. solve form one of the variables from one of the equations
Let's solve for a from 2a + 2s = 40
2a + 2s = 40
2a + 2s - 2s = 40 - 2s
2a = 40 - 2s
2a/2 = 40/2 - 2s/2
a = 20 - s
2. Replace the expression found and solve for s
4a + 5s = 87
4(20 - s) + 5s = 87
4×20 - 4×s + 5s = 87
80 - 4s + 5s = 87
80 + s = 87
80 - 80 + s = 87 - 80
s = 7
3. Replace 7 for s into a = 20 - s
a = 20 - 7
a = 13
Then, a = 13 and s = 7.
Then the adult ticket cost is $13 and the student ticket cost is $7
Step-by-step explanation:
Yearly salary
$ 120,000
Monthly salary
$ 10,000
Biweekly salary
$ 4,615
Weekly salary
$ 2,308
Daily salary
$ 462
Hourly salary
$ 61.54
HOPE THIS HELPS. PLEASE VOTE AS BRAINLIEST.
