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stellarik [79]
2 years ago
11

The figure shows a cylinder on an incline plane of negligible friction. The cylinder is released from rest. Which of the followi

ng correctly describes the change in the motion of the cylinder if the incline is a rough surface?
A. The cylinder rolls down both inclines, with the cylinder taking more time to reach the bottom on the rough surface.
B. The cylinder rolls down both inclines, with the cylinder taking more time to reach the bottom on the surface of negligible friction.
C. The cylinder slides down the incline of negligible friction and rolls down the incline with a rough surface.
D. The cylinder rolls down the incline of negligible friction and slides down the incline with a rough surface.
E. The cylinder rolls down both inclines in the same amount of time.
Physics
1 answer:
vlada-n [284]2 years ago
8 0

Answer:

B

Explanation:

Big Brain enetgy

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 When an electric current flows, the shape of the magnetic field is very similar to the field of a bar magnet

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41. Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 h
romanna [79]

Answer:

138.3 days

Explanation:

Given that a Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 has been discovered and has a radius of 7.8 X 10 meters.

The period of time for Clayton J-21 to orbit Dayli can be calculated by using Kepler law.

T^2 is proportional to r^3

That is,

T^2/r^3 = constant

98^2 / 62^3 = T^2 / 78^3

Make T^2 the subject of formula.

T^2 = 98^2 / 62^3 × 78^3

T^2 = 19123.2

T = sqrt ( 19123.2 )

T = 138.2867 days

Therefore, the period of time for Clayton J-21 to orbit Dayli is 138.3 days approximately.

4 0
3 years ago
A century ago, swords were made from various metals, especially steel. The property that makes steel a good choice for sword mak
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The answer is a solid
5 0
3 years ago
In a ballistics test, a 52g bullet hits a sand bag and stops after moving 1.34 m. If the initial bullat
olya-2409 [2.1K]

Answer:

Friction force on the bullet is 58.7 N opposite to its velocity

Explanation:

As we know that initial speed of the bullet is 55 m/s

after travelling into the sand bag by distance d = 1.34 m it comes to rest

so final speed

v_f = 0

now we can use kinematics top find the acceleration of the bullet

v_f^2 - v_i^2 = 2 a d

so we have

0 - 55^2 = 2(a)(1.34)

a = -1128.7 m/s^2

now by Newton's II law we know that

F = ma

so we have

F = (0.052)(-1128.7)

F = -58.7 N

8 0
3 years ago
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