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Lapatulllka [165]
2 years ago
6

An applied force of 50 N is used to accelerate an object, that weighs 73 N, to the right across a frictional surface. The object

encounters 10 N of friction. What is the acceleration of the object?
Physics
1 answer:
Hunter-Best [27]2 years ago
6 0

Answer:

5.38 m/s^2

Explanation:

NET force causing the object to accelerate  =  50 -10 = 40 N

Mass of the object =  73 N / 9.81 m/s^2 = 7.44 kg

F = ma

40 = 7.44 * a         a = 5.38 m/s^2

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1km=10^3 m,1km^3=10^9cubic metres answer is 1.4x10^18cubic meters
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A tank is filled with an ideal gas at 400 K and pressure of 1.00 atm.
bekas [8.4K]

To find the temperature it is necessary to use the expression and concepts related to the ideal gas law.

Mathematically it can be defined as

PV=nRT

Where

P = Pressure

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T = Temperature

When the number of moles and volume is constant then the expression can be written as

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Or in practical terms for this exercise depending on the final temperature:

T_2 = \frac{P_2T_1}{P_1}

Our values are given as

T_1 = 400K\\P_1 = 1atm\\P_2 = 2atm

Replacing

T_2 = \frac{(2)(400)}{1}\\T_2 = 800K

Therefore the final temperature of the gas is 800K

6 0
3 years ago
Which Equation will you use to solve this question (use the chart at the end of the lesson) While skiing, Sam flies down a hill
ozzi

A.Momentum Equation

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Using the momentum equation , momentum is given as

P = mv

P = 75 x 18

P = 1350 kgm/s

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4 years ago
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¿Qué nombre recibe un electrón que abandona el espacio interno del átomo dirigiéndose al exterior del átomo?
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Answer:

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3 years ago
A small but measurable current of 5.8 × 10-10 A exists in a copper wire whose diameter is 3.0 mm. The number of charge carriers
swat32

Answer:

a) The current density ,J = 2.05×10^-5

b) The drift velocity Vd= 1.51×10^-15

Explanation:

The equation for the current density and drift velocity is given by:

J = i/A = (ne)×Vd

Where i= current

A = Are

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n = volume

Given: i = 5.8×10^-10A

Raduis,r = 3mm= 3.0×10^-3m

n = 8.49×10^28m^3

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J = (5.8×10^-10) /(2.83×10^-5)

J = 2.05 ×10^-5

b) Drift velocity, Vd = J/ (ne)

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