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luda_lava [24]
3 years ago
14

A 70 kilogram hockey player skating east on an ice rink is hit by a 0.1 kilogram hockey puck moving toward the west. The puck ex

erts a 50 newton force toward the west on the player. Determine the magnitude of the force that the player exerts on the puck during this collision
Physics
1 answer:
guajiro [1.7K]3 years ago
4 0

Given:

70 Kilogram hockey

Hit by 0.1 kilogram

50 Newton

Description:

So in this case this bacially means that one object is experiencing a force then another object.  So the answer to the question will be 50N.

Answer: 50N (3rd Law)

Hope this helps.

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Answer:

1. A

2. B

Explanation:

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3 0
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A driver in a car traveling at a speed of 21.8m/s sees a cat 101 m away on the road. How long will it take for the car to accele
kobusy [5.1K]
The acceleration of the car will be needed in order to calculate the time. It is important to consider that the final speed is equal to zero:

v^2 = v_0^2 + 2ad\ \to\ a = \frac{-v_0^2}{2d} = -\frac{21.8^2\ m^2/s^2}{2\cdot 99\ m} = -2.4\frac{m}{s^2}

We can clear time in the speed equation:

v = v_0 + at\ \to\ t = \frac{-v_0}{a} = \frac{-21.8\ m/s}{-2.4\ m/s^2} = \bf 9.08\ s

If you find some mistake in my English, please tell me know.
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3 years ago
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A convex mirror, like the passenger-side rearview mirror on a car, has a focal length of -3.0 m . An object is 6.0 m from the mi
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A) -2.0 m

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Each tick represents 1 m

We have

p = 6.0 m is the distance of the object from the mirror

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From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so

q = -2.0 m

This can also be verified by using the mirror equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-3.0 m}-\frac{1}{6.0 m}=-\frac{3}{6.0 cm}\\q = \frac{-6.0 cm}{3}=-2.0 cm

B) Upright and virtual

As we see from the picture, the image is upright, since it has same orientation as the object.

Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,

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Therefore, this means that the image is virtual.

8 0
3 years ago
g n diffraction, the formula for minima is given by a times s i n (theta )equals m lambda, where a is the width of the slit, the
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Answer:

θ = 22.2

Explanation:

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        a sin θ = m λ

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         sin  θ = 3 630 10⁻⁹ / 5 10⁻⁶

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to better see the result let's find the angle in radians

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let's reduce to degrees

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4 0
3 years ago
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zubka84 [21]

Answer:

Explanation:

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4 0
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