A 70 kilogram hockey player skating east on an ice rink is hit by a 0.1 kilogram hockey puck moving toward the west. The puck ex
erts a 50 newton force toward the west on the player. Determine the magnitude of the force that the player exerts on the puck during this collision
1 answer:
Given:
70 Kilogram hockey
Hit by 0.1 kilogram
50 Newton
Description:
So in this case this bacially means that one object is experiencing a force then another object. So the answer to the question will be 50N.
Answer: 50N (3rd Law)
Hope this helps.
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<span>Matter can change its state because of the pressure and/or the temperature.</span>
Answer:
0.82 MPa
Explanation:
the change in pressure 'σ'=160kPa
K= σ/∈
=> σ/3∈
K= 160/(3 x 0.065)
K=820 kPA=0.82 MPa
Thus,the bulk modulus of the tissue 'K' is 0.82 MPa
Answer:
f = 692 N
Explanation:
given data:
f =800N
a =1.2 m s^{2}
m= 90 kg
from newton's second law
net force 
therefore we have from above equation
ma =F - f
putting all value to get force of friction
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