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bekas [8.4K]
3 years ago
12

Que es determinar ?ayuda porfavor ​

Physics
1 answer:
REY [17]3 years ago
3 0
La palabra 'determinar' es un verbo que se utiliza para señalar la acción de establecer un tipo de dato o información, así como también fijar o hacer claros los elementos de una situación, cosa o evento. La acción de determinar implica siempre una toma de decisión que tiene como consecuencia una resolución que deberá ser tomada en cuenta a partir del momento. Esta resolución puede conocerse como una determinación, y esta palabra se puede encontrar en muchos diversos ámbitos.
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10. Calculate the kinetic energy of a running back that has a mass of 80 kg and
EastWind [94]

Answer:

The answer is

<h2>2560 J</h2>

Explanation:

The kinetic energy of an object given it's mass and velocity can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}

where

m is the mass

v is the velocity

From the question

m = 80 kg

v = 8 m/s

The kinetic energy is

KE =  \frac{1}{2}  \times 80 \times  {8}^{2}  \\  = 40 \times 64

We have the final answer as

<h3>2560 J</h3>

Hope this helps you

5 0
3 years ago
What instrument can you use to measure the circumference of your waist?
wolverine [178]
<h2><em><u>Answer</u></em>:</h2>

<h3>A <u>measuring tape</u> can be used to measure the circumference of your waist.</h3>
3 0
4 years ago
Read 2 more answers
A particle at 9 AM is moving towards the east at 4 ms At 12 noon, it changes its velocity and starts moving towards the north un
nexus9112 [7]

Answer:

Explanation:

Acceleration is the time rate of change of velocity.

Acceleration and velocity are vectors

If east and north are the positive directions, the east moving vector is reduced to zero and the north moving vector increases from zero to 4 m/s.

There are 3 hours or 10800 seconds between 10 AM and 1 PM

a1 = √((-4)² + 4²) / 10800 = (√32) / 10800 m/s² ≈ 4.2 x 10⁻⁴ m/s²

There are 14400 seconds between 10 AM and 2 PM

The velocity changes are still the same

a2 = √((-4)² + 4²) / 10800 = (√32) / 14400 m/s² ≈ 3.9 x 10⁻⁴ m/s²

7 0
3 years ago
Which condition is required for Coulomb's law to hold true?
AleksAgata [21]
The correct answer is:
<span>Point charges must be in a vacuum.

In fact, the usual form for of the Coulomb's law is:
</span>F= \frac{1}{4 \pi \epsilon_0}  \frac{q_1 q_2}{r^2}
<span>where
</span>\epsilon_0 is the permittivity of free space
<span>q1 and q2 are the two charges
q is the separation between the two charges

However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
</span>F= \frac{1}{4 \pi \epsilon_0 \epsilon_r} \frac{q_1 q_2}{r^2}
where \epsilon_r is the relative permittivity, which takes into account the dielectric effects of the material.
7 0
3 years ago
What class lever is a stapler? Explain why.
zimovet [89]
Hi , a class 2 lever has the load between the force and the fulcrum .So a stapler is a good example.
7 0
3 years ago
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