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3 years ago

10. Calculate the kinetic energy of a running back that has a mass of 80 kg and

Physics

1 answer:

EastWind [94]3 years ago

5 0

Answer:

The answer is

Explanation:

The kinetic energy of an object given it's mass and velocity can be found by using the formula

$KE = \frac{1}{2} m {v}^{2}$

where

m is the mass

v is the velocity

From the question

m = 80 kg

v = 8 m/s

The kinetic energy is

$KE = \frac{1}{2} \times 80 \times {8}^{2} \\ = 40 \times 64$

We have the final answer as

Hope this helps you

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You skip north for 12 minutes to your best friend's house that is 1.5 kilometers away. What is your average velocity?

bagirrra123 [75]

Answer:

The average velocity is 7.5 km/h

Explanation:

Let's convert minutes to hours so our answer can be given in a common units of km/hour:

12 minutes = 12/60 hours = 0.2 hours

Now we estimate the average velocity calculating the distance travelled over the time it took:

1.5 / 0.2 km/h = 7.5 km/h

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3 years ago

A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres

Lemur [1.5K]

Answer:

$V_2 = 0.125 m^3$

Work done = = 5 kJ

Explanation:

Given data:

volume of nitrogen $v_1 = 0.08 m^3$

$P_1 = 150 kPa$

$T_1 = 200 degree celcius = 473 Kelvin$

$P_2 = 80 kPa$

Polytropic exponent n = 1.4

$\frac{T_2}{T_1} = [\frac{P_2}{P_1}]^{\frac{n-1}{n}$

putting all value

$\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}$

$\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS$

polytropic process is given as

$P_1 V_1^n = P_2 V_2^n$

$150\times 0.08^{1.4} = 80 \times V_2^{1.4}$

$V_2 = 0.125 m^3$

work done $= \frac{P_1 V_1 -P_2 V_2}{n-1}$

$= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}$

= 5 kJ

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3 years ago

What is the difference between a partial and total lunar eclipse?

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Answer:

During a total lunar eclipse, the moon and sun are on the exact opposite sides of the Earth, leaving the moon entirely in the Earth's shadow. During a partial lunar eclipse, only part of the moon is in the Earth's shadow.

Explanation:

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2 years ago

What is the difference between transverse and longitudinal waves? Transverse waves always have greater frequencies than do longi

Anastasy [175]

Answer:

Explanation:

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3 years ago

An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2010 × 103 seconds (about

vazorg [7]

Answer:

Radial acceleration of moon is $a_{r} = 2.246\times 10^{-3}$ $\frac{m}{s^{2} }$

Explanation:

Given :

Time period $T = 1.987 \times 10^{6}$ sec

Distance from center of moon to planet $r = 225 \times 10^{6}$ m

From the equation of radial acceleration,

$a_{r} = r\omega ^{2}$

Where $\omega = 2\pi f = \frac{2\pi }{T}$

So $\omega = 3.16 \times 10^{-6} \frac{rad}{s}$

Now moon's radial acceleration,

$a_{r} = 225 \times 10^{6} \times (3.16 \times 10^{-6} )^{2}$

$a_{r} = 2246.76 \times 10^{-6}$

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3 years ago