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pogonyaev
2 years ago
12

Which condition is required for Coulomb's law to hold true?

Physics
1 answer:
AleksAgata [21]2 years ago
7 0
The correct answer is:
<span>Point charges must be in a vacuum.

In fact, the usual form for of the Coulomb's law is:
</span>F= \frac{1}{4 \pi \epsilon_0}  \frac{q_1 q_2}{r^2}
<span>where
</span>\epsilon_0 is the permittivity of free space
<span>q1 and q2 are the two charges
q is the separation between the two charges

However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
</span>F= \frac{1}{4 \pi \epsilon_0 \epsilon_r} \frac{q_1 q_2}{r^2}
where \epsilon_r is the relative permittivity, which takes into account the dielectric effects of the material.
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What is the velocity of a beam of electrons that goes undeflected when passing through perpendicular electric and magnetic field
goldenfox [79]
F = qE + qV × B
where force F, electric field E, velocity V, and magnetic field B are vectors and the × operator is the vector cross product. If the electron remains undeflected, then F = 0 and E = -V × B
which means that |V| = |E| / |B| and the vectors must have the proper geometrical relationship. I therefore get
|V| = 8.8e3 / 3.7e-3
= 2.4e6 m/sec
Acceleration a = V²/r, where r is the radius of curvature.
a = F/m, where m is the mass of an electron,
so qVB/m = V²/r.
Solving for r yields
r = mV/qB
= 9.11e-31 kg * 2.37e6 m/sec / (1.60e-19 coul * 3.7e-3 T)
= 3.65e-3 m
6 0
2 years ago
A radio technician measures the frequency of an AM radio transmitter. The frequency is . What is the frequency in megahertz? Wri
sukhopar [10]

Complete Question

A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.

Answer:

The value is  x =  14.6 \  MHz

Explanation:

From the question we are told that

  The  frequency is  f =  14603  \  kHz = 14603 *1000 = 14603000 \ Hz

Generally  

       1 Hz \to  1.0 *10^{-6} \  MHz

       14603000 \ Hz  \to x MHz

=>   x =  \frac{14603000 *  1.0*10^{-6}}{1 }

=>    x =  14.6 \  MHz

8 0
2 years ago
A 60 g ball of clay is thrown horizontally at 40 m/s toward a 1.5 kg block sitting at rest on a frictionless surface. the clay h
Bingel [31]
The solution for this problem is:
Let u denote speed. 

Equating momentum before and after collision: 
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= 2.4 = 1.56 u
= 2.4 / 1.56 = 1.56 u / 1.56
= 1.6 m / s is the answer for this question. This is the speed after the collision.
7 0
2 years ago
What happens when you dip open bottle in bucket full of water?why​?<br>chapter=pressure​
Degger [83]

Answer: It goes inside filling most of it .

Explanation: This happens because the bottle is empty and the bucket is full of water.

3 0
3 years ago
At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 2
likoan [24]
100kg x bicycle speed = 1400 X 2

bicycle speed = 2800/ 100
bicycle speed = 28 m/s
3 0
3 years ago
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